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otez555 [7]
4 years ago
7

What is an equation of the line that passes through the points (0, -5) and (-5,-1)?

Mathematics
2 answers:
Y_Kistochka [10]4 years ago
5 0

Answer:

y=-\frac{4}{5}x-5

Step-by-step explanation:

The coordinates (0,-5) tells us the y intercept of the line, which is -5.

To find the equation of the line, we  have to use the equation m=\frac{y2-y1}{x2-x1} to find the slope of the line. Plug in the values of the other coordinates (-5,-1) into the equation, which would then leave you with :

m=\frac{(-1)-(-5)}{(-5)-0}

we then solve for m(the slope) and we get:

m=-\frac{4}{5}

so the equation of the line is y=-\frac{4}{5}x-5

Mazyrski [523]4 years ago
3 0

Answer:

we find first slope

m=(-5+1)/(0+5)

m=-4/5

y-y1=m(x-x1)

y+ 5=(-4/5)(x-0)

5y+25=-4x

so equation is. 4x+5y+25=0

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Because ΔQRS is congruent to <span>ΔTUV, the the segments GS and TV are also congruent due to the letter order (Q and T are first and S and V are 3rd.) Since they are congruent QS=TV. So 3v + 2 = 7v - 6
</span><span>
</span><span>Work: 
</span>3v + 2 = 7v - 6
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3v + 8=7v
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Final Answer: 8=QS and 8=TV

 
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