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Lena [83]
3 years ago
7

Could someone show me how you would factorise : 9a(squared) - 6ab + 12ac - 8bc

Mathematics
1 answer:
wlad13 [49]3 years ago
4 0
9a^2 -6ab+ 12ac -8bc

This expression cannot be factorized because its terms don't have at least a common factor~
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Question
rodikova [14]

Answer:

Volume = 11488.21

Area = 2461.76

Step-by-step explanation:

Given

Radius, r = 14\ in

Shape: Sphere

Solving (a): The Volume

This is calculated as:

Volume = \frac{4}{3}\pi r^3

Take \pi as 3.14 and substitute 14 for r

Volume = \frac{4}{3} * 3.14 * 14^3

Volume = \frac{4}{3} * 3.14 * 2744

Volume = \frac{4 * 3.14 * 2744}{3}

Volume = \frac{34464.64}{3}

Volume = 11488.21

Solving (b): The Surface Area

This is calculated as follows:

Area = 4\pi r^2

Take \pi as 3.14 and substitute 14 for r

Area = 4 * 3.14 * 14^2

Area = 4 * 3.14 * 196

Area = 2461.76

7 0
2 years ago
Juan earns $55,000 a year. His taxes are 10% of his earnings. How much does he pay in taxes?
lana66690 [7]

Answer:

5,500

Step-by-step explanation:

this is quite simple

multiply his earnings by a tenth

55,000 times 1/10

5,500

5 0
3 years ago
Read 2 more answers
7) If £1 = €1.14.<br> Work out what €144 is in pounds.
jonny [76]

Answer:

126\frac{6}{19} £

Step-by-step explanation:

£1 = €1.14  /*\frac{144}{1.14}

£\frac{144}{1.14}=144€= 126\frac{6}{19} \\£

8 0
2 years ago
HELP DUE IN 10 MINUTES!
vfiekz [6]

Answer:

68

Step-by-step explanation:

97.65 is roughly 100

68℅ of 100 is 68

so it's 68

5 0
3 years ago
Read 2 more answers
Given: △ACM, m∠C=90°, CP ⊥ AM
larisa86 [58]

Answer:  The answer is 3\dfrac{4}{7}.

Step-by-step explanation:  Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.

Now,

AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)

Comparing equations (A) and (B), we have

5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.

Thus,

AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.

8 0
3 years ago
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