Answer:
Events A and B are independent but Event C is dependent on both Event A and Event B.
Step-by-step explanation:
Find whether events A, B and C are independent.
- Events A and B are independent of each other, because the appearance of an odd number on die X does not effect or influence the appearance of an even number on die Y.
- Event C, on the other hand, is dependent on both event A and event B. How?
For Event C to take place, one die will have to show an odd number while the other shows an even number.
NOTE: The odd number must not show up on die X and the even number show up on die Y. Both number types can appear on any die.
The key is just that one number must be odd and the other even; in order for their sum to be an odd number.
Answer:
The polynomial of degree 3 ,P(x), has a root of multiplicity 2 at x=1 and a root of multiplicity 1 at x=−1. The y-intercept is y=−0.2
Answer:
I think it's 8
Step-by-step explanation:
you take away -1 because its the same
then you count units between 0 and 9
Answer:

Step-by-step explanation:
we have

Solve for t
That means ----> Isolate the variable t
Multiply by b both sides to remove the fraction

Factor t left side
![t[b+a]=b](https://tex.z-dn.net/?f=t%5Bb%2Ba%5D%3Db)
Divide by (b+a) both sides

Answer:
A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (3), B (4), C (2), and D (3). The grading system assigns quality points as follows: A: 4; B: 3; C: 2; D: 1; and F: 0. Find the student’s GPA for this semester. Round your answer to the nearest thousandth.
another way is
This is a weighted average question. You are going to "weight" each course by the number of credits it is worth and then divide by the total number of credits. In other words, you are going to multiply each grade (A=4, B=3) by the number of credits attached to that grade. This will ensure that the courses that have more credits count more in the overall average. Then you are going to divide by the total number of credits to get the overall GPA.
So,
(3*4 + 4*3 + 2 *2 + 3*1)/(3+4+2+3) = GPA
Step-by-step explanation:
bran-list please