A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (
4), B (3), F (3), A (2) and D (1). The grading system assigns quality points as follows: A: 4; B: 3; C: 2; D: 1; and F: 0. Find the student’s GPA for this semester. Round your answer to the nearest thousandth (three decimals).
A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (3), B (4), C (2), and D (3). The grading system assigns quality points as follows: A: 4; B: 3; C: 2; D: 1; and F: 0. Find the student’s GPA for this semester. Round your answer to the nearest thousandth.
another way is
This is a weighted average question. You are going to "weight" each course by the number of credits it is worth and then divide by the total number of credits. In other words, you are going to multiply each grade (A=4, B=3) by the number of credits attached to that grade. This will ensure that the courses that have more credits count more in the overall average. Then you are going to divide by the total number of credits to get the overall GPA.
Because X and Y vary directly, the equation is the form Y =KX. We can then solve for K by using the given values for X and Y. The equation that relates X and Y is Y= 5x
I set up the equations x + y = 24 and x*y=-3468. Then I substituted for y and used the quadratic formula to come to two numbers rounded to about 72.1 and -48.1. Hope that helps :)
