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Kipish [7]
3 years ago
8

Use 751,486 what is the digit in the thousands pace

Mathematics
2 answers:
Mars2501 [29]3 years ago
8 0
The number in the thousands place: 1
lora16 [44]3 years ago
4 0
The digit in the thousands place is 1
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PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK​
Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

\sf \cos(\theta)=\dfrac{A}{H}

where:

  • \theta is the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

  • \theta = ∠KLM
  • A = LN = 8
  • H = KL = 15.2

\implies \sf \cos(KLM)=\dfrac{8}{15.2}

\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)

\implies \sf \angle KLM=58.24313614^{\circ}

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}

Given:

  • r = 15.2
  • ∠KLM = 58.24313614°

\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)

\implies \textsf{Arc length MK}=\sf 15.45132428\:units

6 0
2 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
olchik [2.2K]

Answer:

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation y=-16x^2+224x+121. We are asked to find the time, when the rocket will hit the ground.

We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute y=0 in our given equation as:

0=-16x^2+224x+121

Let us solve for x using quadratic formula.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-224\pm\sqrt{224^2-4(-16)(121)}}{2(-16)}

x=\frac{-224\pm\sqrt{50176+7744}}{-32}

x=\frac{-224\pm\sqrt{57920}}{-32}

x=\frac{-224\pm240.66574}{-32}

x=\frac{-224+240.66574}{-32}, x=\frac{-224-240.66574}{-32}

x=\frac{16.66574}{-32}, x=\frac{-464.66574}{-32}

x=-0.520804375, x=14.520804375

Upon rounding to nearest 100th of second, we will get:

x\approx -0.52, x\approx 14.52

Since time cannot be negative, therefore, the rocket will hit the ground after 14.52 seconds.

6 0
4 years ago
Read 2 more answers
Find the second, fourth, and eleventh terms of the sequence A(n) = 5 + (n - 1)(-3)​
klio [65]

Answer:

2nd: 2

4th: -4

11th: -25

Step-by-step explanation:

When you substitute a number into the equation you get that number term. So, if you substituted in 1, you get the first term. To find the second term, you substitute in 2:

A(2) = 5 + (2 - 1)(-3)

A(2) = 5 + (1)(-3)

A(2) = 5 - 3

A(2) = 2

To get the 4th term you substitute in 4:

A(4) = 5 + (4 - 1)(-3)

A(4) = 5 + (3)(-3)

A(4) = 5 - 9

A(4) = -4

And we do the same for the 11th term:

A(11) = 5 + (11 - 1)(-3)

A(11) = 5 + (10)(-3)

A(11) = 5 - 30

A(11) = -25

8 0
3 years ago
What is the vertex of the quadratic function y=-x²+6x+7? ​
vichka [17]

Answer:

(3,16)

Step-by-step explanation:

Factor the equation to find out that the roots are 7 and -1. The vertex's x will be in the center of these two points, so the center point between 7 and -1 is 3. Continue to substitute the x in the equation with 3 to get the other coordinate for vertex.

6 0
3 years ago
What is the point-slope form of a line thats has a slope of-4 and passes through point (-3,1)
ANEK [815]

Answer:

y - 1 = -4(x+3)

Step-by-step explanation:

We will use the point slope form of a line

y-y1 = m(x-x1)  where m is the slope and (x1,y1) is the point

y - 1 = -4(x--3)

y - 1 = -4(x+3)

4 0
4 years ago
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