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3 years ago

What is the value of the expression (-8/9) + (-2/3) x (-4 1/2)

Mathematics

1 answer:

geniusboy [140]3 years ago

6 0

$\frac{4}{9}$

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Samantha has $24 but she wants a pair of Jordan's that are $112. She does chores and she gets paid $5 for each chore. If she doe

natita [175]

Answer:

Check step-by-step.

Step-by-step explanation:

Okay, so. She gets 5 dollars and she does 15 chores. You would multiply it.

5 * 15 = $75

Then you would subtract 112 and 75.

112 - 75 = 37.

She will get $75. Then, she will need to gather $37

6 0

3 years ago

A square has side length (x+5) units. What is it’s area

daser333 [38]

The area of square is $x^{2}+10 x+25$ square units

<h3><u>Solution:</u></h3>

Given that square has side length (x+5) units

To find: area of square

<em><u>The area of square is given as:</u></em>

$\text {Area of square }=\mathrm{a}^{2}$

Where "a" is the length of side

From question, length of each side "a" = x + 5 units

Substituting the value in above formula,

$\text {Area of square }=(x+5)^{2}$

${\text {Expanding }(x+5)^{2} \text { using the algebraic identity: }} \\\\ {(a+b)^{2}=a^{2}+2 a b+b^{2}}\end{array}$

$\begin{array}{l}{\text {Area of square }=x^{2}+2(x)(5)+5^{2}} \\\\ {\text {Area of square }=x^{2}+10 x+25}\end{array}$

Thus the area of square is $x^{2}+10 x+25$ square units

7 0

3 years ago

For the circle with equation (x-2)^2+(y+3)^2=9, answer each question. a) whats coords of the center? b) what are the radius and

MrRissso [65]

Answer:

<h2>a) center (2, -3)</h2><h2>b) radius r = 3</h2><h2>c) in the attachment</h2>

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have:

$(x-2)^2+(y+3)^2=9\\\\(x-2)^2+(y-(-3))^2=3^2$

a) center (2, -3)

b) radius r = 3

c) in the attachment

4 0

3 years ago

Which number line shows the solution to 11x + 14 <-8

kkurt [141]

Answer:

The answer is D

Step-by-step explanation:

I did it on edg

8 0

3 years ago

A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m

photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

Mass of the car, v1 = 1500 kg

initial speed of car = 35 miles/h

$=\dfrac{35\times 1609.34}{3600}\ m/s$

= 15.64 m/s

Initial kinetic energy of the car is given by,

$k_1\ =\ \dfrac{1}{2}.m.v_1^2$

$=\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule$

= 183606.46 J

Final velocity of car v2 = 70 miles/hour

$=\dfrac{70\times 1609.34}{3600}$

= 31.29 m/s

So, final kinetic energy of car is given by

$k_2\ =\ \dfrac{1}{2}.m.v_2^2$

$=\ \dfrac{1}{2}\times 1500\times (31.29)^2$

= 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

$\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}$

$=>\ k_2\ =\ 4k_1$

Hence, the kinetic energy will increase by 4 times.

7 0

3 years ago