Here, you're mixing scores 85 and 90 with weights X and Y, respectively. You are asked for the ratio of X to Y.
There's a quick way to work mixture problems of all kinds. Write the two components of the mixture on the left. Here, they are 90 and 85. (I usually put the larger one on top.) Put the mixed value in the middle, and form differences along the lines of an X, as shown. The numbers on the right give the relative contributions of the constituents at the same level in the diagram. Here, the ratio of X to Y is shown as 2 to 3.
For some mixture problems, you need to know the proportion of the constituent to the whole. In that case, add the ratio values to get the "whole". For example, here the X class students make up 2/(2+3) = 2/5 of the whole number of students.
For your problem, X/Y = 2/3, corresponding to selection D.
Answer:62019
Step-by-step explanation:
Answer:
the position of a particle moving at a coordinate say(y) will satisfy the given conditions t=0 (say) if y=2sint-cost
Step-by-step explanation:
Clearly by the above we can see that if y=2sint-cost at t=0, then y=-1 because at t=0 sint vanishes and leaves us with only cost and at t=0 cos0=1
Answer:
1) -8h and 4h
2) 3t and 7t
3) -4e and 3e
4) -2b and b
Step-by-step explanation:
They all have the same variable as the other in the pair. There aren't any other variables added or exponents.
We can make the ratio better by converting the relationship into whole numbers.
2/20 : 1/40
Simplify first.
1/10:1/40
Multiply by 40.
answer: 4:1