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Anuta_ua [19.1K]
3 years ago
11

Mario and Bowser begin with a hat that has 5 balls in it: 3 are red, 2 are green. Bowser secretly picks a ball and tells Mario i

t is red, although he might be lying about the color. If there is an 80% chance Bowser is lying, what is the probability that Mario draws 2 red balls in a row after Bowser's initial draw?
Mathematics
1 answer:
stiv31 [10]3 years ago
8 0
1) probabillity of getting two red balls in a row is 1/2 (if 80% Bowser is lying)
2) <span>probability of getting 2 red balls in a row is 1/6 (20% Bowser's truth)
3)  overall probability </span>( \frac{4}{5} * \frac{1}{2}) + (\frac{1}{5} * \frac{1}{6}) = \frac{13}{30}
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Consider the equation below (in screenshot)
frozen [14]

The <em>approximate</em> solution of the equation shown in the picture is x ≈ 39 / 8 (Right choice: B).

<h3>How to find an approximate solution of a one-variable equation</h3>

The solution of the equation is between x = 4 and x = 5. Now we begin by evaluating each side of the expression (f(x) = x² - 5 · x + 4, g(x) = 2 / (x - 1)) at the average of x = 4 and x = 5.

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f(4.5) = 4.5² - 5 · 4.5 + 1

f(4.5) = - 5 / 4

g(4.5) = 2 / (4.5 - 1)

g(4.5) = 4 / 7

The solution of the equation is between x = 4.5 and x = 5, then we evaluate at the average:

x = (4.5 + 5) / 2

x = 4.75

f(4.75) = 4.75² - 5 · 4.75 + 1

f(4.75) = - 3 / 16

g(4.75) = 2 / (4.75 - 1)

g(4.75) = 8 / 15

The solution of the equation is between x = 4.75 and x = 5, then we evaluate at the average:

x = (4.75 + 5) / 2

x = 4.875

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g(4.875) = 2 / (4.875 - 1)

g(4.875) = 16 / 31

The <em>approximate</em> solution of the equation shown in the picture is x ≈ 39 / 8 (Right choice: B).

To learn more on successive approximations: brainly.com/question/27191494

#SPJ1

7 0
2 years ago
Fundamental theorem of calculus<br> <img src="https://tex.z-dn.net/?f=g%28s%29%3D%5Cint%5Climits%5Es_6%20%7B%28t-t%5E4%29%5E6%7D
mr_godi [17]

Answer:

\displaystyle g'(s) = (s-s^4)^6

Step-by-step explanation:

The Fundamental Theorem of Calculus states that:
\displaystyle \frac{d}{dx}\left[ \int_a^x f(t)\, dt  \right] = f(x)

Where <em>a</em> is some constant.

We can let:
\displaystyle g(t) = (t-t^4)^6

By substitution:

\displaystyle g(s) = \int_6^s g(t)\, dt

Taking the derivative of both sides results in:
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Hence, by the Fundamental Theorem:

\displaystyle \begin{aligned} g'(s) & = g(s) \\ \\  & = (s-s^4)^6\end{aligned}

3 0
2 years ago
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