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3 years ago

Find the interquartile range of the data.

Mathematics

2 answers:

LekaFEV [45]3 years ago

8 0

Answer:

D.20

Step-by-step explanation:

Median: 30

Lower quartile: 16

Upper quartile: 36

Interquartile range: 36 - 16 = 20

kati45 [8]3 years ago

5 0

The interquartile range of the data is the answer C. 20.

Interquartile Range = Upper Quartile - Lower Quartile
Interquartile Range = 36 - 16
Interquartile Range = 20

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A car costs 20% less this year than last year. Last year, the car cost 5% less than the year before. The price of the car this y

Tems11 [23]

Answer:

The answer is 11,374

Step-by-step explanation:

First we find 5% of 9,400 is.

9,400 * 5% = 470

Next we add 9,400 with 470 then multiply by 20%

9,400 + 470 = 9,870

9,870 * 20% = 1974

Next we add.

9,870 + 1,974 = 11,374

So, the answer is 11,374

Hope this helps! :)

3 0

3 years ago

Mike has a collection of 140 canada stamps ,284 mexico stamps and 775 united states stamps about how many united states and cana

Doss [256]

Answer:

915 stamps

Step-by-step explanation:

140 + 775 = 915

4 0

3 years ago

Can someone help me with this problem? am i right? this is 7th grade btw.

labwork [276]

I think you are right, it is (1,1).

6 0

3 years ago

What are the values of x and y. In the given figure?

anyanavicka [17]

Answer:

y = 52 degrees

x = 7 degrees

Step-by-step explanation:

Hello! So, we can first easily find out the measurement of y because of the Base Angles Theorem.

[ The base angles theorem converse states if two angles in a triangle are congruent, then the sides opposite those angles are also congruent. The Isosceles Triangle Theorem states that the perpendicular bisector of the base of an isosceles triangle is also the angle bisector of the vertex angle. ]

- www.ck12.org

So basically, in an iscoceles triangle, the base angles are equal so therefore, y = 52 degrees

Now we have to solve for x. We know that the sum of the angles in a triangle are 180 so we have to make an equation:

52 + y = 14x + 6 {We know that y is 52 degrees so we should plug that in}

52 + 52 = 14x + 6 --> Now we should simplify:

104 = 14x + 6

98 = 14x

x = 7 degrees

6 0

3 years ago

Read 2 more answers

Suppose that a basketball player can score on a particular shot with probability .3. Use the central limit theorem to find the a

Rom4ik [11]

Answer:

(a) The probability that the number of successes is at most 5 is 0.1379.

(b) The probability that the number of successes is at most 5 is 0.1379.

(d) The probability that the number of successes is at most 11 is 0.9357.

→ All the exact probabilities are more than the approximated probability.

Step-by-step explanation:

Let S = a basketball player scores a shot.

The probability that a basketball player scores a shot is, P (S) = p = 0.30.

The number of sample selected is, n = 25.

The random variable $S\sim Bin(25,0.30)$

According to the central limit theorem if the sample taken from an unknown population is large then the sampling distribution of the sample proportion ( $\hat p$ ) follows a normal distribution.

The mean of the the sampling distribution of the sample proportion is: $E(\hat p)=p=0.30$

The standard deviation of the the sampling distribution of the sample proportion is:

$SD(\hat p)=\sqrt{\frac{ p(1- p)}{n} }=\sqrt{\frac{ 0.30(1-0.30)}{25} }=0.092$

(a)

Compute the probability that the number of successes is at most 5 as follows:

The probability of 5 successes is: $p=\frac{5}{25} =0.20$

$P(\hat p\leq 0.20)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq \frac{0.20-0.30}{0.092} )\\=P(Z\leq -1.087)\\=1-P(Z$

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 5 is 0.1379.

The exact probability that the number of successes is at most 5 is:

$P(S\leq 5)={25\choose 5}(0.30)^{5}91-0.30)^{25-5}=0.1935$

The exact probability is more than the approximated probability.

(b)

Compute the probability that the number of successes is at most 7 as follows:

The probability of 5 successes is: $p=\frac{7}{25} =0.28$

$P(\hat p\leq 0.28)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq \frac{0.28-0.30}{0.092} )\\=P(Z\leq -0.2174)\\=1-P(Z$

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 7 is 0.4129.

The exact probability that the number of successes is at most 7 is:

$P(S\leq 57)={25\choose 7}(0.30)^{7}91-0.30)^{25-7}=0.5118$

The exact probability is more than the approximated probability.

(c)

Compute the probability that the number of successes is at most 9 as follows:

The probability of 5 successes is: $p=\frac{9}{25} =0.36$

$P(\hat p\leq 0.36)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq \frac{0.36-0.30}{0.092} )\\=P(Z\leq 0.6522)\\=0.7422$

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 9 is 0.7422.

The exact probability that the number of successes is at most 9 is:

$P(S\leq 9)={25\choose 9}(0.30)^{9}91-0.30)^{25-9}=0.8106$

The exact probability is more than the approximated probability.

(d)

Compute the probability that the number of successes is at most 11 as follows:

The probability of 5 successes is: $p=\frac{11}{25} =0.44$

$P(\hat p\leq 0.44)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq \frac{0.44-0.30}{0.092} )\\=P(Z\leq 1.522)\\=0.9357$

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 11 is 0.9357.

The exact probability that the number of successes is at most 11 is:

$P(S\leq 11)={25\choose 11}(0.30)^{11}91-0.30)^{25-11}=0.9558$

The exact probability is more than the approximated probability.

6 0

4 years ago