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3 years ago

5

Find the interquartile range of the data.

2 answers:

LekaFEV [45]3 years ago

8 0

Answer:

<em>D.20</em>

Step-by-step explanation:

Median: 30

Lower quartile: 16

Upper quartile: 36

Interquartile range: 36 - 16 = 20

kati45 [8]3 years ago

5 0

The interquartile range of the data is the answer C. 20.

Interquartile Range = Upper Quartile - Lower Quartile
Interquartile Range = 36 - 16
Interquartile Range = 20

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To the nearest millimeter, a cell phone is 82 mm long and 36 mm wide. What is the ratio of the width to the length?

iVinArrow [24]

<h2>The ratio of the width to the length of a cell phone is 18 : 41.</h2>

Step-by-step explanation:

Given,

The length of a cell phone(l) = 82 mm and

The width of a cell phone(b) = 36 mm

Find, the ratio of the width to the length of a cell phone = ?

∴ The ratio of the width to the length of a cell phone

= 36 mm : 82 mm

= 36 : 82

Divided by 2, we get

= $\dfrac{36}{2}$ : $\dfrac{82}{2}$

= 18 : 41

Thus, the ratio of the width to the length of a cell phone is 18 : 41.

3 0

3 years ago

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deff fn [24]

Answer:

Step-by-step explanation:

x = 106

4 0

3 years ago

Read 2 more answers

Bill wants to rent a car. Rental Company A charges $35 per day plus $0.10 per mile driven. Rental Company B charges $25 per day

m_a_m_a [10]

M represents miles
35+0.10m=25+0.15m
35-25+0.10m=25-25+0.15m
10+0.10m=0.15m
10+0.10m-0.10m=0.15m-0.10m
10=0.05m
m=200
Check:
35+0.10(200)=25+0.15(200)
35+20=25+30
55=55
The solution: m=200 is true.
After 200 miles driven, prices charged by both companies will be the same.

7 0

4 years ago

Finding Hypotenuse Lengths. Find the length of the hypotenuse.

ioda

Answer:

11) $\frac{3\sqrt{5}}{2}$

12) $4\sqrt{5}$

13) $22$

14) $18$

15) $2$

16) $24\sqrt{3}$

Step-by-step explanation:

For these problems I used the pythagorean theorem: $a^{2}+ b^{2}= c^{2}$ and SOHCAHTOA

Sin = $\frac{opposite}{hypotenuse}$

Cos = $\frac{adjacent}{hypotenuse}$

Tan = $\frac{opposite}{hypotenuse}$

11)

First find the length of the bottom side by using Cos

$cos(60)=\frac{x}{3}$

$3(cos(60))=x$

$1.5=x$

Then plug it into the formula for the pythagorean theorem to find the hypotenuse

$3^{2}+ 1.5^{2}= c^{2}$

$9+2.25=c^{2}$

$\sqrt{11.25}=\sqrt{c^{2}}$

$\frac{3\sqrt{5}}{2}$

12)

Find the length of the bottom side using Cos

$cos(60)=\frac{x}{8}$

$8(cos(60))=x$

$4=x$

Then plug it into the formula for the pythagorean theorem to find the hypotenuse

$8^{2}+ 4^{2}= c^{2}$

$64+16=c^{2}$

$\sqrt{80} =\sqrt{c^{2} }$

$4\sqrt{5}$

13)

Find the length of the other side by using Tan

$tan(30)=\frac{x}{11\sqrt{3} }$

$11\sqrt{3}* (tan(30)=x$

$11=x$

Then plug it into the formula for the pythagorean theorem to find the hypotenuse

$(11\sqrt{3}) ^{2}+ 11^{2}= c^{2}$

$363+121=c^{2}$

$\sqrt{484} =\sqrt{c^{2}}$

$22$

14)

(This is probably an easier way to do these problems)

Find the hypotenuse by using Cos ( $\frac{adjacent}{hypotenuse}$ )

$cos(60)=\frac{9}{x}$

$cos(60)x=9$

$x=\frac{9}{cos(60)}$

$x=18$

15)

Find the hypotenuse using Sin ( $\frac{opposite}{hypotenuse}$ )

$sin(30)=\frac{1}{x}$

$sin(30)x=1\\x=\frac{1}{sin(x)}$

$x=2$

16)

Find the hypotenuse using Cos ( $\frac{adjacent}{hypotenuse}$ )

$cos(60)=\frac{12\sqrt{3} }{x}$

$cos(60)x=12\sqrt{3}$

$x=\frac{12\sqrt{3} }{cos(60)}$

$x=24\sqrt{3}$

5 0

4 years ago

Help me plsss right answer !!!!

riadik2000 [5.3K]

Answer: 6

Step-by-step explanation:

For every 6 bagels, two are blueberry.

8 0

3 years ago

Read 2 more answers