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Romashka [77]
3 years ago
15

What's 50*20*30*100*300=?

Mathematics
2 answers:
fomenos3 years ago
6 0

Answer:

900000000

Hope this helps!!

olga2289 [7]3 years ago
3 0

Answer:

It's 900,000,000

Step-by-step explanation:

Multiply them all together.

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Mark wants to improve his free throw percentage in basketball He has shot 1,250 free throws over the last 20 days. He shot eithe
Sedaia [141]
Let's use a for number of days when he shot 50 shots and b for number of days when he shot 100 shots.
We have:
a + b = 20

We also know that he shot total of 1250 shots:
50a + 100 b = 1250

We have two equations. We can solve them for a and b.  Let's rearange first equation for a:
a= 20 - b
We insert this into second equation:
50 * (20 - b ) + 100b = 1250
1000 - 50b + 100b = 1250
50b = 250
b = 5
a = 20 - 5
a = 15

Mark shot 100 shots on 5 days.
4 0
3 years ago
Situation D: Suppose that, in a one-minute period during an electrical storm, the number of lightning strikes on a radar antenna
Crank

Answer:

21.77% probability that the antenna will be struck exactly once during this time period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

In this question:

\mu = 2.40

Find the probability that the antenna will be struck exactly once during this time period.

This is P(X = 1).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 1) = \frac{e^{-2.40}*2.40^{1}}{(1)!} = 0.2177

21.77% probability that the antenna will be struck exactly once during this time period.

3 0
3 years ago
Find the solution(s) to the system <br>y = x2-4 <br>y = -2x – 5 <br><br>​
katen-ka-za [31]

Answer:

=(-1,-5)

Step-by-step explanation:

y=X1=4

y=-2x-5-2

4 0
2 years ago
3. For the following system of equations, complete a table of at least 5 points for each equation, then graph the system on the
8090 [49]

Answer:

I'll do it for the equation, then you can try to solve the second one. Of your not able to, just comment and I'll answer the second one

Step-by-step explanation:

y = -3x+4

When

___x__l  _y____

   0          l    4

   1           l     1

   2          l     -2

   3          l     -5

   4          l     -8

6 0
3 years ago
If quadrilateral adqu is congruent to quadrilateral teki then quad is congruent to ____
Xelga [282]

Answer:

KITE

Step-by-step explanation:

We are given that,

Quadrilateral ' adqu ' is congruent to quadrilateral ' teki '.

i.e. adqu ≅ teki

Now, when two figures are congruent the position of the letters are very important.

Using the positioning of the letters, we will find the quadrilateral congruent to ' quad '.

So, we see that the correspondence of letters is given by q → k, u → i, a → t and d → e.

Therefore, quad ≅ kite.

Hence, Quadrilateral ' quad ' is congruent to quadrilateral ' kite '.

7 0
3 years ago
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