I believe it’s 4 since you have to go to class and introduce yourself to the teachers so he/she will know you better and know how they can help you and when going to their office hours they can help you with anything that you are having trouble with.
Answer:
$1,935.90
Explanation:
We prepare a Bank Reconciliation Statement to determine the reconciled balance as follows :
<u>Erin Garnder</u>
<u>Bank Reconciliation Statement</u>
Balance as per Bank Statement $2,087.93
Add Outstanding Lodgments $813.11
Less Unpresented checks
($224.15 + $327.80 + $88.10 + $122.42 + $202.67) ($965.14)
Balance as per Cash Book $1,935.90
Therefore,
The reconciled balance is: $1,935.90
HEY THERE WHATS UP
THE ANSWER IS:<span>C. lower prices and more goods.
HOPE IT HELPS</span>
Answer:
Variable manufacturing overhead rate variance= $677.1 unfavorable
Explanation:
Giving the following information:
Standard:
Variable overhead 0.3 hours $ 7.80 per hour
Actual output 5,000 units
Actual direct labor-hours 1,110 hours
Actual variable overhead cost $ 9,340
<u>To calculate the variable overhead rate variance, we need to use the following formula:</u>
Variable manufacturing overhead rate variance= (standard rate - actual rate)* actual quantity
Actual rate= 9,340/1,110= $8.41
Variable manufacturing overhead rate variance= (7.8 - 8.41)*1,110
Variable manufacturing overhead rate variance= $677.1 unfavorable
Answer:
(a) 75% (b) 25% (c) 2.25 customers (d) 12 minutes (e) 0.25 (f)0.237
Explanation:
Solution
Given that:
The Arrival rate at Poisson distribution = 15 per hour = λ
The Service rate at exponential distribution = 20 per hour = μ
(a) System utilization = λ/μ = 15 / 20 = 0.75 = 75%
(b) The Probability of zero requests in server = 1 - λ/μ = 1 - 0.75 = 0.25
or
The percentage of time server will be idle = 25%
(c)The expected number of customers waiting to be served = Average number of customers in line = λ^2/μ (μ-λ ) = 225 /20(20-15) = 45 /20 = 2.25
Therefore, it is expected that on an average, 2.25 customers are waiting in line to get served.
(d)The average time customers will spend in system = 1/(μ-λ )
=1/(20 - 15) = 1/5 hours = 12 minutes
(e)The probability of zero customer in system = 1 -λ/μ = 1 - 0.75 = 0.25
(f) The probability of more than 4 customers in the system = (λ/μ)^ 4+1
= (15/20)5 = 0.237