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Ilya [14]
3 years ago
6

How many solutions are there for the system of equations shown on the graph? A coordinate plane is shown with two lines graphed.

One line crosses through the x axis at negative 4 and the y axis at 2. The other crosses through the x axis at negative 4 and the y axis at 2. No solution One solution Two solutions Infinitely many solutions
Mathematics
1 answer:
seropon [69]3 years ago
4 0
So two points for the first line are (-4,0) and (0, 2) so the slope of this line is:

m=(2--4)/(0--4)=6/4=1.5  and we can see from point to that b, the y-intercept is 2 so the line is:

y=1.5x+2

The second line has the same points and is therefore the same line, so there are infinitely many solutions.
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Nidah writes down two different prime numbers.
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Willing to brainlist solve 16-17 please during this exam
ivann1987 [24]

Answer:

16. B

17. B

Step-by-step explanation:

16. The intercept form of the parabola is

y=a(x-x_1)(x-x_2),

where x_1, x_2 are two x-intercepts.

In your case,

x_1=2\\ \\x_2=-8

so

y=a(x-2)(x-(-8))\\ \\y=a(x-2)(x+8)

To find <em>a</em>, substitute coordinates of the point (-6,-4) parabola is passing through

-4=a(-6-2)(-6+8)\\ \\-4=-16a\\ \\a=\dfrac{1}{4}

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17. The vertex form of the parabola equation is

-2p(y-k)=(x-h)^2,

where <em>(h,k)</em> are the coordinates of the vertex and sign "-" because parabola goes down.

In your case, vertex is (2,3), so

-2p(y-3)=(x-2)^2

The vertex is 3 units from the focus, then

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The equation of the parabola is

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8 0
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