Answer:
Attachment 1 : 5x + 6y = 5, Attachment 2 : 4cotθcscθ
Step-by-step explanation:
Remember that we have three key points in solving these types of problems,
• x = r cos(θ)
• y = r sin(θ)
• x² + y² = r²
a ) For this first problem we need not apply the third equation.
( Multiply either side by 5 cos(θ) + 6 sin(θ) )
r 
( 5 cos(θ) + 6 sin(θ) ) = 5,
( Distribute r )
5r cos(θ) + 6r sin(θ) = 5
( Substitute )
5x + 6y = 5 - the correct solution is option c
b ) We know that y² = 4x ⇒
r²sin²(θ) = 4r cos(θ),
r = 4cos(θ) / sin²(θ) = 4 cot(θ) csc(θ) = 4cotθcscθ - again the correct solution is option c
Answer:
Step-by-step explanation:
We can use the quadratic formula or factor, This looks hard to factor so we should use the quadratic formula.
ax^2 + bx + c
so
a=4
b=-9
c=2
you can try it by hand or use this:
https://www.calculatorsoup.com/calculators/algebra/quadratic-formula-calculator.php
you get x=2 and x=0.25 these are the x intercepts (where Y is zero and where the graph crosses the x axis)
so mark x=2 and x=0.25 with a dot on a number line and you can draw a straight line between them since that is the part of the graph that is below the x axis (because the equation has <0) it is a positive parabola because the "a" value is positive and the presence of a "b" value means part of the graph will be below the x axis
If you have an equation like 4 + w = 12, you'll work backward to find w by subtracting 4 from 12.
Or if you have an equation like 4r = 24, you'll work backward by dividing 24 by 4 to find r.
Answer:
4 is the answer is it right
280+220=500 hope this helps
