Answer:
Option A - Neither. Lines intersect but are not perpendicular. One Solution.
Option B - Lines are equivalent. Infinitely many solutions
Option C - Lines are perpendicular. Only one solution
Option D - Lines are parallel. No solution
Step-by-step explanation:
The slope equation is known as;
y = mx + c
Where m is slope and c is intercept.
Now, two lines are parallel if their slopes are equal.
Looking at the options;
Option D with y = 12x + 6 and y = 12x - 7 have the same slope of 12.
Thus,the lines are parrallel, no solution.
Two lines are perpendicular if the product of their slopes is -1. Option C is the one that falls into this category because -2/5 × 5/2 = - 1. Thus, lines here are perpendicular and have one solution.
Two lines are said to intersect but not perpendicular if they have different slopes but their products are not -1.
Option A falls into this category because - 9 ≠ 3/2 and their product is not -1.
Two lines are said to be equivalent with infinitely many solutions when their slopes and y-intercept are equal.
Option B falls into this category.
The answer and process is shown in the following picture
Answer:
Patricia spent $24 on presents, while Donald spent $12 and Carl spent $36.
Step-by-step explanation:
The problem is to solve how much money each person spent on presents in the year, through a series of equivalences. In order to determine how much money each one spent, the following equation must be proposed:
Patricia = X
Donald = 1 / 2X
Carl = 3/2 X
X + 1 / 2X + 3 / 2X = 72
1X + 0.5 X + 1.5 X = 72
3X = 72
X = 72/3
X = 24
Thus, Patricia spent $ 24 on presents, while Donald spent $ 12 (2/24) and Carl spent $ 36 (1.5 x 24).
Answer:
The correct option is (A).
Step-by-step explanation:
The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

Here,
AGE = age counted in years
PA = appropriate physical activity factor
WT = weight in kilograms
HT = height in meters
The physical activity factor for men and women is:
Activity Level PA (men) PA (Women)
Sedentary 1.00 1.00
Low 1.11 1.12
Active 1.25 1.27
Very Active 1.48 1.45
Given:
AGE = 22 year-old male college student
PA = low = 1.11
WT = 180 pounds = 81.6466 kg
HT = 5'10" = 1.778 m
Compute the value of EER as follows:


Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.
The correct option is (A).