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tino4ka555 [31]

3 years ago

11

pritz makes 7 2/3 pints of pineapple juice she drank 5/6 pints of juice and poured. 3/4 of the remaining juice equally into 3 bo

ttles how much pineapple juice does each bottle contain

1 answer:

kirza4 [7]3 years ago

7 0

Answer:

45

Step-by-step explanation:

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Which function has the greatest starting value?. . A.. xy. 1−3. 2−8. 3−13. . . B.. y = 3x – 8. . C.. 8x + 4y = 16. . D.. A linea

nasty-shy [4]

The problem ask to choose among the following functions in the given choices that has the greatest value and the best answer among the following function is letter D. a linear function that goes through point 2,0 and point 0,2. I hope you are satisfied with my answer

5 0

3 years ago

Initially a tank contains 10 liters of pure water. Brine of unknown (but constant) concentration of salt is flowing in at 1 lite

zhenek [66]

Answer:

Therefore the concentration of salt in the incoming brine is 1.73 g/L.

Step-by-step explanation:

Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.

Let the concentration of salt be a gram/L

Let the amount salt in the tank at any time t be Q(t).

$\frac{dQ}{dt} =\textrm {incoming rate - outgoing rate}$

Incoming rate = (a g/L)×(1 L/min)

=a g/min

The concentration of salt in the tank at any time t is = $\frac{Q(t)}{10}$ g/L

Outgoing rate = $(\frac{Q(t)}{10} g/L)(1 L/ min)$ $\frac{Q(t)}{10} g/min$

$\frac{dQ}{dt} = a- \frac{Q(t)}{10}$

$\Rightarrow \frac{dQ}{10a-Q(t)} =\frac{1}{10} dt$

Integrating both sides

$\Rightarrow \int \frac{dQ}{10a-Q(t)} =\int\frac{1}{10} dt$

$\Rightarrow -log|10a-Q(t)|=\frac{1}{10} t +c$ [ where c arbitrary constant]

Initial condition when t= 20 , Q(t)= 15 gram

$\Rightarrow -log|10a-15|=\frac{1}{10}\times 20 +c$

$\Rightarrow -log|10a-15|-2=c$

Therefore ,

$-log|10a-Q(t)|=\frac{1}{10} t -log|10a-15|-2$ .......(1)

In the starting time t=0 and Q(t)=0

Putting t=0 and Q(t)=0 in equation (1) we get

$- log|10a|= -log|10a-15| -2$

$\Rightarrow- log|10a|+log|10a-15|= -2$

$\Rightarrow log|\frac{10a-15}{10a}|= -2$

$\Rightarrow |\frac{10a-15}{10a}|=e ^{-2}$

$\Rightarrow 1-\frac{15}{10a} =e^{-2}$

$\Rightarrow \frac{15}{10a} =1-e^{-2}$

$\Rightarrow \frac{3}{2a} =1-e^{-2}$

$\Rightarrow2a= \frac{3}{1-e^{-2}}$

$\Rightarrow a = 1.73$

Therefore the concentration of salt in the incoming brine is 1.73 g/L

8 0

3 years ago

Select all the equations that are equivalent to this equation.<br> 1/4 (8X + 56) = 20<br> 56 + 8X = 80<br> 14 = 20 – 8x<br> 2X +

Leya [2.2K]

1/4(8x+56)=20
1/4(8x)+1/4(56)=20
2x+14=20
2x=20-14
2x=6
X=3

3 0

2 years ago

Consider the line y = 2x–4.

choli [55]

Parallel slope = 2

This is because the original line has slope 2. Parallel lines have equal slopes.

--------------------------

Perpendicular slope = -1/2

The original slope 2 or 2/1 turns into -1/2 after flipping the fraction and the sign. Note the original slope and perpendicular slope multiply to -1. This is true for any pair of perpendicular lines where neither line is vertical.

8 0

3 years ago

Read 2 more answers

. 25% of 900 = 225, 25% is called____ *

posledela

Answer:

25% is called a quarter of 900

Step-by-step explanation:

${ \tt{25\% = \frac{25}{100} = \frac{1}{4} }} \\$

4 0

2 years ago

Read 2 more answers