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iren [92.7K]
2 years ago
12

Hi can somebody check if this is correct please?

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
8 0

Answer:

No, it is incorrect. The line should be solid, not dotted, because it's a ≤ sign, not a < sign.

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Which of the following expressions has a value of 2/5 in the picture below?
Anuta_ua [19.1K]

Step-by-step explanation:

<u>Step 1:  List out all of the formulas for the trigonometric functions </u>

<em>sin(x) </em>= opposite/hypotenuse

<em>cos(x) </em>= adjacent/hypotenuse

<em>tan(x) </em>= opposite/adjacent

<u>Step 2:  Find the following expression that has a value of 2/5 </u>

sin(B) = opposite/hypotenuse = ?/5 is FALSE

cos(B) = adjacent/hypotenuse = 2/5 is TRUE

tan(B) = opposite/adjacent = ?/2 is FALSE

Answer:  The correction expression that has a value of 2/5 is option B

5 0
3 years ago
Which statement best describes the polynomial?
amid [387]

Answer:-12x^{2}-9x-4584671418

Step-by-step explanation:

4 0
3 years ago
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What is 289% as a decimal
lakkis [162]

Answer:

the answer is 2.89

Step-by-step explanation:

u divide 289 to 100 or 289/100=2.89

hope this helps

4 0
3 years ago
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The temperature at 12 am was 44 degrees. The temperature dropped steadily for the next 8 hours to reach the daytime low of 20 de
adelina 88 [10]

Answer:

62 degrees

Step-by-step explanation:

Points (12,440 and (20,20)

Slope = -3

Equation of line: y - 44 = -3(x - 12)

Plug in x = 6 to get y = 62.

6 0
3 years ago
After traveling exactly half of its journey from station A to station B, a train was held up for 10 minutes. In order to arrive
Alex17521 [72]
Let's define variables:
 s = original speed
 s + 12 = faster speed
 The time for the half of the route is:
 60 / s
 The time for the second half of the route is:
 60 / (s + 12)
 The equation for the time of the trip is:
 60 / s + 60 / (s + 12) + 1/6 = 120 / s
 Where,
 1/6: held up for 10 minutes (in hours).
 Rewriting the equation we have:
 6s (60) + s (s + 12) = 60 * 6 (s + 12)
 360s + s ^ 2 + 12s = 360s + 4320
 s ^ 2 + 12s = 4320
 s ^ 2 + 12s - 4320 = 0
 We factor the equation:
 (s + 72) (s-60) = 0
 We take the positive root so that the problem makes physical sense.
 s = 60 Km / h
 Answer:
 
The original speed of the train before it was held up is:
 
s = 60 Km / h
8 0
3 years ago
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