Answer:
Step-by-step explanation:
Part A= 59.11
Part B: i think is B
I hope this helps :))
With digits 8, 5, and 6, an odd number must end in 5.
So far, we have _ _ 5.
The 8 is in the hundreds place.
Now we have 8_5.
The only place left for the 6 is the tens place.
The number is 865.
Answer:
Area of the shaded region = 1.72r²
Step-by-step explanation:
Radius of the circle = r
Length of the rectangle = 4r
Width of the rectangle = 2r
Area of the circle = πr²
Area of the rectangle = Length × Width
= 4r × 2r
= 8r²
Area of the shaded region = Area of the rectangle - 2 × Area of the circle
= 8r² - 2 × πr²
= 8r² - 2πr²
= r²(8 - 2π)
= r²(8 - 2 × 3.14)
= r²(8 - 6.28)
= 1.72r² 
Answer:
{0.16807, 0.36015, 0.3087, 0.1323, 0.02835, 0.00243}
Step-by-step explanation:
The expansion of (p+q)^n for n = 5 is ...
(p+q)^5 = p^5 +5·p^4·q +10·p^3·q^2 +10·p^2·q^3 +5·p·q^4 +q^5
When the probability p=0.3 and q = 1-p = 0.7 the terms of this series correspond to the probabilities of 5, 4, 3, 2, 1, and 0 favorable outcomes out of 5 trials.
For example, p^5 = 0.3^5 = 0.00243 is the probability of 5 favorable outcomes in 5 trials where the probability of each favorable outcome is 0.3.
___
The attachment shows the calculation of these numbers using a graphing calculator. It lists them in reverse order of the expansion of (p+q)^5 shown above, so that they are the probabilities of 0–5 favorable outcomes in the order 0–5.
Answer:
Length = 3 cm
Width = 1 cm
Step-by-step explanation:
Let the length of rectangle be l and width of rectangle be w.
According to problem,
l = 3w {Length of rectangle is equal to triple the width}
And Perimeter,P = 8 cm
Since, P = 2 ( l + w )
or 8 = 2( l + w)
Plug l =3w in the above perimeter equation.
We get:
8 = 2( 3w + w)
8 = 2(4w)
8 = 8w
or w = 1 cm
Then length ,l = 3w =3 * 1 = 3 cm
Hence length of rectangle is 3cm and width of rectangle is 1cm.