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VashaNatasha [74]
3 years ago
10

for each one fifth, use a horizontal line or lines to show fractions equivalent to 1/5 and write the equivalent fractions

Mathematics
1 answer:
Zina [86]3 years ago
3 0

Answer:

2/10 3/15

Step-by-step explanation:

Simplifying these answers equals 1/5

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What is the volume of the prism
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Textbook: Please write as an expression involving functions of Θ alone.
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Step-by-step explanation:

tan(Θ + 30°)

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(tan Θ + 1/√3) / (1 − 1/√3 tan Θ)

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6 0
3 years ago
Pls solve part b) iii thanks
Viktor [21]

The bearing of the tree from Q is 296.565°

<h3>How to determine the height of the tree?</h3>

The figure that illustrates the bearing and the distance is added as an attachment

The given parameters are:

Base of the tree, b = 50 meters

Angle (x) = 32 degrees

Calculate the height (h) of the tree using:

tan(x) = height/base

So, we have:

tan(32°) = h/50

Make h the subject

h= 50 × tan(32°)

Evaluate

h = 31.24

Hence, the height of the tree is 31.24 meters

<h3>How to determine the distance between Q and the base of the tree?</h3>

The distance (d) between Q and the base of the tree

This is calculated using the following Pythagoras theorem

d = √(100² + 50²)

Evaluate

d = 111.80

Hence, the distance between Q and the base of the tree is 111.80 meters

<h3>How to determine the angle of elevation?</h3>

The angle of elevation (x) using the following tangent trigonometric ratio

tan(x) = h/d

This gives

tan(x) = 31.24/111.80

Evaluate the quotient

tan(x) = 0.2794

Take the arc tan of both sides

x = 15.61

<h3>The bearing of the tree from Q </h3>

This is calculated using:

Angle of bearing = 270 + arctan(50/100)

Evaluate the arc tan

Angle of bearing = 270 + 26.565

Evaluate the sum

Angle of bearing = 296.565

Hence, the bearing of the tree from Q is 296.565 degrees

Read more about bearings at:

brainly.com/question/24142612

#SPJ1

4 0
2 years ago
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