As, v=√2as
Squaring both sides,
v²=2as
∴ s= v²/2a
First of all, we can observe that

So the expression becomes

This means that the expression is defined for every 
Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

Since we can't accept 3 as an answer, the actual solution set is
![(-\infty,-2] \cup [2,3) \cup (3,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C-2%5D%20%5Ccup%20%5B2%2C3%29%20%5Ccup%20%283%2C%5Cinfty%29)
Answer:
It's D
Step-by-step explanation:
2t - 30(
) = 20
2t -
(
) = 20
2t -
= 20
2t - 6 = 20
2t - 6 + 6 = 20 +6
2t = 26
= 
t = 13
He should draw six faces, since there are six faces on a rectangle.