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Mariana [72]
3 years ago
7

Round 3.5555 to the nearest thousandth

Mathematics
2 answers:
MatroZZZ [7]3 years ago
7 0
 is arround 3.556 by the nearest thousandth
Dmitriy789 [7]3 years ago
4 0
3.556 is the correct answer
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The length of a rectangle is 2 meters less than 2 times the width. The perimeter is 20 meters. Find the width.
kakasveta [241]
The equation you'd make would be (2x-2)+(2x-2)+x+x=20 because the length is 2 m less than the width (x). To simplify, it'd be 6x-4=20 because you combine like terms. You then move the -4 over to the 20 to make it 6x=24. The final answer is 4 meters.
4 0
4 years ago
Find two consecutive even integers such that the square of the first, decreased by the second is 130
marta [7]
Let's make the first even integer m and the second even integer n. The square of the first, decreased by the second is 130 is:

m^{2}-n=130  ---> Add n to each side
m^{2}=130+n ---> Take the square root of each side
m=±\sqrt{130+n}

Let's look at the first square number above 130, which is 12^{2}. <em>m</em> is 12, therefore the next consecutive even integer is 14.

12^{2}=144
144-14=130

The two consecutive integers are 12 and 14
5 0
4 years ago
I) Solve the equation sin2x + 3cos2x = 0 (for 0 till 360°)
galina1969 [7]
Get rid of cos2x by dividing both the values. So Sin2x/cos2x +3cos2x/cos2x.
Tan2x = 3
2x = -71.5 so x is -35.6
Use the quadrant method and add 360 twho the two values tou get.
7 0
3 years ago
Sandy charges each family that she babysits a flat fee of 10$ for the night and an extra 5$ per child kimmi charges 25$ per nigh
Rudiy27
Sandy's cost equation is y = 5x + 10 where y = cost and x = number of children.
Kimmi's cost equation is y = 25 where y = cost.
The fees are the same when x = 3 in other words when Sandy babysits 3 children.
That is found by solving 5x + 10 = 25 for x.
Subtract 10 from each side: 5x = 15
Divide by 5 on both sides: x = 3
5 0
4 years ago
PLEASE HELP ME! IT WOULD BE VERY MUCH APPRECIATED!
puteri [66]

Answer:

it's the last one

Step-by-step explanation:

hope this helped :)

8 0
4 years ago
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