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Lina20 [59]
4 years ago
14

Find two consecutive even integers such that the square of the first, decreased by the second is 130

Mathematics
1 answer:
marta [7]4 years ago
5 0
Let's make the first even integer m and the second even integer n. The square of the first, decreased by the second is 130 is:

m^{2}-n=130  ---> Add n to each side
m^{2}=130+n ---> Take the square root of each side
m=±\sqrt{130+n}

Let's look at the first square number above 130, which is 12^{2}. <em>m</em> is 12, therefore the next consecutive even integer is 14.

12^{2}=144
144-14=130

The two consecutive integers are 12 and 14
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