3 years ago

Never mind free points and brainlest

Mathematics

2 answers:

Colt1911 [192]3 years ago

4 0

Wait on god ? You frfr

S_A_V [24]3 years ago

3 0

Thank you!!!!!!!!!!!!!!!!!!!!!!!!!

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What is the domain of f?

larisa86 [58]

Answer:

$\huge \boxed{\mathrm{A}}$

Step-by-step explanation:

The domain of a function is all possible values for the value of x.

The denominator in a rational function cannot equal to 0.

$x+2\neq 0$

Subtracting 2 from both sides.

$x\neq -2$

The domain of the function is all real numbers except -2.

7 0

3 years ago

In a translation, what math process is used? WILL GIVE BRAINILEST!!!

jekas [21]

The answer is B multiplication That’s correct who is the

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3 years ago

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Find the values of a through e that make these two relations inverses of each other.

yuradex [85]

Answer:

hmm I'm pretty sure a is 3.2

4 0

1 year ago

What is the difference in simplest form? <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bn%5E2%2B3n%2B2%7D%7Bn%5E2%2B6n%2B8%7D-%5

Paha777 [63]

$\bf \cfrac{n^2+3n+2}{n^2+6n+8}-\cfrac{2n}{n+4}\implies \cfrac{n^2+3n+21}{(n+4)(n+2)}-\cfrac{2n}{n+4}
\\\\\\
\textit{so our LCD will just be (n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~(n+2)(2n)}{(n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~(2n^2+4n)}{(n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~2n^2-4n}{(n+4)(n+2)}
\implies 
\cfrac{-n^2-n+2}{(n+4)(n+2)}
\\\\\\
\cfrac{-(n^2+n-2)}{(n+4)(n+2)}\implies \cfrac{-\underline{(n+2)}(n-1)}{(n+4)\underline{(n+2)}}\implies \cfrac{-(n-1)}{n+4}\implies \cfrac{1+n}{n+4}$

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3 years ago

Rewrite the equation by completing the square.<br>x^2-2x+1=0

kaheart [24]

Answer:

(x - 1)² = 0

Step-by-step explanation:

Given

x² - 2x + 1 = 0 ( subtract 1 from both sides )

x² - 2x = - 1

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 1)x + 1 = - 1 + 1

(x - 1)² = 0

5 0

3 years ago