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marysya [2.9K]
3 years ago
12

What is the answer to 7x+5y=-66​

Mathematics
2 answers:
OverLord2011 [107]3 years ago
6 0

Since this does not have two equations, many answers are acceptable.

One of these is x = -8, y = -2.

sergejj [24]3 years ago
4 0

Answer:

The answer will be x = - 66/7 - 5y/7

Step-by-step explanation:

I'm not sure what the context of the problem is, however just shoot me another question if this seems incorrect.

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I just need anyone to tell me if it's correct:<br><br> Is 8: True<br> and<br> Is 9: False<br> ?
natta225 [31]
I’m pretty sure

8. would be false because BK would be 12 where as DF is 10.8

9. is true
4 0
3 years ago
Read 2 more answers
Find the volume of this hexagonal prism.
Arisa [49]
I hope you get it
The answer 2338.2 cm^3

5 0
3 years ago
Simplify.<br><br> 4 x (8 + 5) + 9 can someone help me out plz
Xelga [282]

Step-by-step explanation:

4x(8+5)+9

=52x+9

=52x+9

Description:

The first step is to simplify the equation provided. So in this case the equation is 4 x (8 + 5) + 9.  After that you will get your answer as =52x+9. So in this case 4 x (8 + 5) + 9 = =52x+9.

Answer: =61

Hope this helps.

8 0
3 years ago
Read 2 more answers
How do I do 8b(ii) ? Please help me thank you!
Mila [183]
Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)]                                           \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2      Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2    Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2   Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.


7 0
3 years ago
What is the area of a square with side lengths of 3/5 units?
umka2103 [35]

Answer:

We must solve 3/5 x 3/5.

3/5 x 3/5 = 0.36

The units we'll use is  because units are the unt we're given, and it is squared because it is the area of a shape.

Your final answer is 0.36

6 0
3 years ago
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