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3 years ago

What is the answer to 7x+5y=-66

Mathematics

2 answers:

OverLord2011 [107]3 years ago

6 0

Since this does not have two equations, many answers are acceptable.

One of these is x = -8, y = -2.

sergejj [24]3 years ago

4 0

Answer:

The answer will be x = - 66/7 - 5y/7

Step-by-step explanation:

I'm not sure what the context of the problem is, however just shoot me another question if this seems incorrect.

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What is 15.63 + 24.36

raketka [301]

Answer:

<u>The Answer would be 39.99</u>

8 0

4 years ago

Read 2 more answers

Paul and Cindy own different pizza shops. Paul makes 12 pizzas the first day and 6 pizzas each day after that. Cindy makes 16 pi

pishuonlain [190]

The right answer is Option C.

Step-by-step explanation:

Given,

Pizzas made by Paul on first day = 12

Pizzas made each day after that = 6

Let,

p represent the number of pizzas made after first day.

Total pizzas = 6p + 12

Number of days = 8 because first day 12 pizzas are made

Total pizzas = $6(8)+12=60$

Pizzas made by Cindy on first day = 16

Pizzas made each day after that = 4

Total pizzas = 4p + 16

Total pizzas = $4(8)+16=48$

Paul has made more pizzas after 9 days. He has made 60 pizzas.

The right answer is Option C.

Keywords: comparison, addition

Learn more about addition at:

#LearnwithBrainly

6 0

3 years ago

Is 4.05 greater than 4.2

Orlov [11]

No
4.2 is greater than 4.05
basically 4.2 is 4.20 and so 4.05 is smaller

6 0

3 years ago

Read 2 more answers

Please help if you can. I will give Brainiest to best answer. This question is a Calculus/Trigonometry question. I ask that you

Ierofanga [76]

7 is incorrect. The answer should be -4. Here's how I'd derive it:

$\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}$

With $\pi$ , we should expect $\cos x$ . If $\tan x=\dfrac8{15}$ , then

$\sec x=-\sqrt{1+\tan^2x}=-\dfrac{17}{15}\implies\cos x=-\dfrac{15}{17}$

Also,

$\pi$

so we should expect $\tan\dfrac x2$ and

$\tan\dfrac x2=-\sqrt{\dfrac{1-\cos x}{1+\cos x}}=-4$

You seem to be taking

$\tan\dfrac x2=\dfrac{1+\cos x}{-\sin x}$

but this is not an identity.

###

8 is incorrect. Just a silly mistake, you swapped the order of the terms in the numerator. It should be

$\dfrac{\sqrt6-\sqrt2}4$

###

9. Use the identity from (7). $\dfrac{7\pi}{12}$ lies in the second quadrant, so

$\tan\dfrac{7\pi}{12}=-\sqrt{\dfrac{1-\cos\frac{7\pi}6}{1+\cos\frac{7\pi}6}}=-\sqrt{7+4\sqrt3}=-2-\sqrt3$

###

12.

$\dfrac{\cot x-1}{1-\tan x}=\dfrac{\frac{\cos x}{\sin x}-1}{1-\frac{\sin x}{\cos x}}$

$=\dfrac{\cos x(\cos x-\sin x)}{\sin x(\cos x-\sin x)}$

$=\dfrac{\cos x}{\sin x}$

$=\dfrac{\csc x}{\sec x}$

###

13.

$\dfrac{1+\tan x}{\sin x+\cos x}=\dfrac{1+\frac{\sin x}{\cos x}}{\sin x+\cos x}$

$=\dfrac{\cos x+\sin x}{\cos x(\sin x+\cos x)}$

$=\dfrac1{\cos x}$

$=\sec x$

###

14.

$\sin2x(\cot x+\tan x)=2\sin x\cos x\left(\dfrac{\cos x}{\sin x}+\dfrac{\sin x}{\cos x}\right)$

$=2\sin x\cos x\dfrac{\cos^2x+\sin^2x}{\sin x\cos x}$

$=2$

###

15.

$\dfrac{1-\tan^2\theta}{1+\tan^2\theta}=\dfrac{1-\frac{\sin^2\theta}{\cos^2\theta}}{1+\frac{\sin^2\theta}{\cos^2\theta}}$

$=\dfrac{\cos^2\theta-\sin^2\theta}{\cos^2\theta+\sin^2\theta}$

$=\cos2\theta$

3 0

3 years ago

Sam is helping Jason do carpentry and general repair jobs. Jason gave Sam some money for supplies. Sam bought some tools for $20

TiliK225 [7]

Answer:

LALLALA IS

Step-by-step explanation:

7 0

3 years ago

What is the answer to 7x+5y=-66​

What is the answer to 7x+5y=-66