Answer: The answer is B
Step-by-step explanation: 122 >7 (z+8) -5 (6+z). Then switch them, 7 (z+8) -5 (6+z) <122. Expanded: 7 (z+8) -5 (6+z) <122:v 2z+26
2z+26<122, subtract 26 from both sides: 2z+26-26<122-26
Simplify: 2z<96, divide both sides by 2: 2z over 2 < 96 over 2
and finally simplified: Z<48
HOPE THIS HELPED YOU OUT!
IF NOT SORRY!
it would be known as a mixed fraction....?
Correct Question:
A car/bus travels at a speed of 45 km/h. How far will it travel in 36 minutes?
(Note- Corrected part is written in bold.)
Solution:








- Hence, a car/bus travels 27 km in 36 mins.
Answer:
maximum height is 4.058 metres
Time in air = 0.033 second
Step-by-step explanation:
Given that the equation height h
h = -212t^2 + 7t + 4
What is the toy's maximum height?
Let us assume that the equation is a perfect parabola
Time t at Maximum height will be
t = -b/2a
Where b = 7 and a = - 212
t = -7/ - 212 ×2
t = 7/ 424 = 0.0165s
Substitute t in the main equation
h = - 212(7/424)^2 + 7(7/424) + 4
h = - 0.05778 + 0.115567 + 4
h = 4.058 metres
Therefore the maximum height is 4.058 metres
How long is the toy in the air?
The object will go up and return to the ground.
At ground level, h = 0
-212t^2 + 7t + 4 = 0
212t^2 - 7t - 4 = 0
You can factorize the above equation and pick the positive time t since time can't be negative
Or
Since we have assumed that it's a perfect parabola,
Total time in air = (-b/2a) × 2
Time in air = 0.0165 × 2 = 0.033 s
Answer:
hello : answer : 3
Step-by-step explanation:
transled :
1 unit right : add 1 for x
2 unit up : add 2 for y
exempl : the image for M ( 1 ; 2) by translation is M'(1+1 ; 2+2) so M' (2 , 2).
the image for P ( 1 ; 3) by translation is P'(1+1 ; 3+2) so M' (2 , 5).
same method for A and T .