Answer:
648
Step-by-step explanation:
Running this in Python, with the code as follows,
import math
cur_numbers = [0] * 3
num = 0
for i in range(100, 1000):
cur_numbers[2] = i % 10
i = math.floor(i/10)
cur_numbers[1] = i % 10
i = math.floor(i/10)
cur_numbers[0] = i % 10
if(len(set(cur_numbers)) == 3):
num += 1
print(cur_numbers)
print(num), we get 648 as our answer.
Another way to solve this is as follows:
There are 9 possibilities for the hundreds digit (1-9). Then, there are 10 possibilities for the tens digit, but we subtract 1 because it can't be the 1 same digit as the hundreds digit. For the ones digit, there are 10 possibilities, but we subtract 1 because it can't be the same as the hundreds digit and another 1 because it can't be the same as the tens digit. Multiplying these out, we have
9 possibilities for the hundreds digit x 9 possibilities for the tens digit x 8 possibilities for the ones digit = 648
Answer:
Step-by-step explanation:
For the null hypothesis,
µ = 60
For the alternative hypothesis,
h1: µ < 60
This is a left tailed test
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 100,
Degrees of freedom, df = n - 1 = 100 - 1 = 99
t = (x - µ)/(s/√n)
Where
x = sample mean = 52
µ = population mean = 60
s = samples standard deviation = 22
t = (52 - 60)/(22/√100) = - 3.64
We would determine the p value using the t test calculator. It becomes
p = 0.00023
We would reject the null hypothesis if α = 0.05 > 0.00023
The solution to the equation is x = 0, 2
The graph is posted
hope that helps :)
Answer:
question is not proper
Step-by-step explanation:
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