Answer:
17.9 m/s
Step-by-step explanation:
Volume of the slick = 0.5 x π r² h--------------------------------- (1)
Where r = radius of slick
h = thickness of slick, 10⁻⁶m
If 0.5m³ of oil leaked, then the radius of the semicircular slick can be calculated from equation (1)
V = 0.5 x π r² h
0.5= 0.5 x π x r² x 10⁻⁶
r² = 10⁶/ π
r = 10³/√π
dV/dt = πrh dr/dt + 0.5π r² dh/dt----------------------------------- (2)
Asumming the film thickness is constant , equation (2) becomes
dV/dt = πrh dr/dt-------------------------------- (3)
dV/dt = 0.1m³/day
r= 10³/√π
dr/dt= rate of expansion of the slick
Substituting into (3);
0.1 = π x 10³/√π x 10⁻⁶ x dr/dt
dr/dt = 0.1 x 10⁶/ ( π x 10³/√π)
= 17.9479 m/s
≅ 17.9 m/s
I think it's C, I could be wrong though
Answer:
cent/km
Step-by-step explanation:
Given
![Unit\ cost = R17.82/litre](https://tex.z-dn.net/?f=Unit%5C%20cost%20%3D%20R17.82%2Flitre)
![Rate = 6.3litre/100km](https://tex.z-dn.net/?f=Rate%20%3D%206.3litre%2F100km)
Required
The fuel cost in ![cent\ per\ km](https://tex.z-dn.net/?f=cent%5C%20per%5C%20km)
This is calculated using:
![Cost = Unit\ cost * Rate](https://tex.z-dn.net/?f=Cost%20%3D%20Unit%5C%20cost%20%2A%20Rate)
![Cost = R17.82/litre * 6.3litre/100km](https://tex.z-dn.net/?f=Cost%20%3D%20R17.82%2Flitre%20%2A%206.3litre%2F100km)
![Cost = R17.82 * 6.3/100km](https://tex.z-dn.net/?f=Cost%20%3D%20R17.82%20%2A%206.3%2F100km)
![Cost = R1.12266/km](https://tex.z-dn.net/?f=Cost%20%3D%20R1.12266%2Fkm)
Multiply by
to get the cost in cents
cent/km
cent/km
A. 3 times 10^4
90000000 divided by 3000 is 30000 which happens to be equal to 3 times 10^4
If you want to learn how to do this just take your whole number ex: 3 and put 10^6 and you will have 3 followed by 6 zeros. The ^ is just how many zeros will follow your whole number at first.
Answer:
The answer is 5
Step-by-step explanation:
Hope it helps <3 c: