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Korolek [52]
3 years ago
13

To be fully prepared for a speech, a student should memorize their speech one week in advance and practice three times everyday.

Please select the best answer from the choices provided T F
SAT
1 answer:
pantera1 [17]3 years ago
8 0

That statement is false

There are other methods that people can for the speech other than memorizing it. Here are two methods that you can use :

- Preparing a text so you can conduct the speech by reading it.

- Preparing a couple of pointers in your hand to help you remember the important topics of the speech.

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Why is the magic number of an atom 8?
Nezavi [6.7K]
In nuclear physics, a magic number is a number of nucleons such that they are arranged into complete shells within the atomic nucleus.
7 0
3 years ago
During the Middle Ages, a musician in a monastery or cathedral would do which of the following
Yuri [45]

During the Middle Ages, a musician in a monastery or cathedral would Sing liturgy. This is further explained below.

<h3>What is Sing liturgy?</h3>

Generally, Designed to remove the devil from our hearts and bring a pure self into contact with God, liturgy is a rite that includes singing, chanting, and sometimes even dancing.

In conclusion, During the Middle Ages, a musician in a cathedral or monastery would be responsible for singing the liturgy.

Read more about Sing liturgy

brainly.com/question/1110953

#SPJ1

6 0
2 years ago
Help me please with it
Lelu [443]

Answer:

D

Explanation:

Double the first equation. Write the second below it. Rearrange the second.

2x - 20 = - 4y

<u>-2x -16= +4y</u>           Add.

- 36 = 0

There is no solution to this pair of equations.

7 0
3 years ago
Read 2 more answers
The number of sp 2 hybrid orbitals on the carbon atom in co 3 2– is
DENIUS [597]

Answer:

1. 2

hope this helps

4 0
2 years ago
Factor the expression into an equivalent form 12y^2-75.
elena-14-01-66 [18.8K]

Hello oddworld7836!

\huge \boxed{\mathbb{QUESTION} \downarrow}

Factor the expression into an equivalent form 12y² - 75.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

12 y ^ { 2 } - 75

By observing the expression, we can see that, 3 is the only common factor in both the terms of the expression. So, take the common factor 3 out.

12 y ^ { 2 } - 75 \\  = 3\left(4y^{2}-25\right)

Now, look at (4y² - 25). They don't have any common factors but they appear in the form of the algebraic identity ⇨ a² - b² = (a + b) (a - b). Here,

  • a² = 4, a = 2 (√a² = ✓4 = 2)
  • b² = 25, b = 5 (√b² = ✓25 = 5)

So, the (4y² + 25) becomes...

(4 {y}^{2}  - 25) \\  = \left(2y-5\right)\left(2y+5\right)

Now, bring the 3 (common factor) & rewrite the complete expression.

12 y ^ { 2 } - 75 \\  =  \boxed{ \boxed{ \bf \: 3\left(2y-5\right)\left(2y+5\right) }}

We can't further simplify it. Also, remember that the simplified form of an expression is equivalent to the expression. So, 3 (2y - 5) (2y + 5) is equivalent to 12y² - 75.

__________________

Hope it'll help you!

ℓu¢αzz ッ

8 0
2 years ago
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