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Arlecino [84]
3 years ago
7

The length of a rope was 6/8 yard.Jeff cut the rope into 3 pieces. Each piece is a different length measured in eighths of a yar

d. What is the length of each piece of rope?
Mathematics
2 answers:
Gelneren [198K]3 years ago
6 0
I'm really bad math !!!
Ratling [72]3 years ago
5 0

The length of the rope was \frac{6}{8} yard

Jeff cut the rope into 3 pieces.

Each piece is a different length measured in eighths of a yard which means that the denominator of each piece should be same which is 8

As each piece is of different length so the numerator of each piece will be different.

But the total of the numerator should be 6

So the numerators will be 1, 2 and 3

Since 1 + 2 + 3 = 6

So length of each piece will be

\frac{1}{8} yard

\frac{2}{8} yard

and \frac{3}{8} yard

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Josh is making 3 recipes one requires 2/3 cups of flour and otherwise 7/8 of a cup of flour in the third requires 3/4 cup of flo
kati45 [8]

Answer:

2 7/24C

Step-by-step explanation:

Start by finding the common denominator. In this case, it's 24. Next, start translation.

2/3C = 16/24C

7/8C = 21/24C

3/4C = 18/24C

Then find the sum.

16/24C + 21/24C + 18/24C = 55/24C = 2 7/24C

5 0
3 years ago
A food processor packages orange juice in small jars. The weights of the filled jars are approximately normally distributed with
Ratling [72]

Answer:

P(X>10.983)=P(\frac{X-\mu}{\sigma}>\frac{10.983-\mu}{\sigma})=P(Z>\frac{10.983-10.5}{0.3})=P(z>1.61)

And we can find this probability using the complement rule and with excel or the normal standard table:

P(z>1.61)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(10.5,0.3)  

Where \mu=10.5 and \sigma=0.3

We are interested on this probability

P(X>10.983)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>10.983)=P(\frac{X-\mu}{\sigma}>\frac{10.983-\mu}{\sigma})=P(Z>\frac{10.983-10.5}{0.3})=P(z>1.61)

And we can find this probability using the complement rule and with excel or the normal standard table:

P(z>1.61)=1-P(z

8 0
3 years ago
rope price of length 45cm 25 cm and 81 cm have to be cut into same size pieces what is the smallest price length possible​
Sergeeva-Olga [200]

= 2025

When you are told to find the smallest length possible, you perform L.C.M(Least common multiples)

For this, you divide the given lengths using the numbers that divides all through.

I have added an image to this answer. Go through it for more explanation

5 0
2 years ago
Please help me solve this proof!!!!!
jolli1 [7]

statements:

1.) E is midpoint of TP

2) TP bisects MR


reasons:

1.)given

2) MT is congruent to PR       (I think)


I might be wrong though so dont count on it being right. I hope I helped. ime not that good at math. I m not BAD but yea



6 0
3 years ago
1 ball of wool is 125m, how many balls are there with 604m??
forsale [732]

Answer:

4.8 balls of wool

Step-by-step explanation:

604÷125=4.8

6 0
2 years ago
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