In my opinion I think it 35
Answer:
1) A and D
The radius is the distance from the center of a circle to any part of the edge. Both A and D have a radius of three, regardless of what direction they go.
2) 5"
In circle C we see that there is a line segment that is 5" that goes from the center to the edge, or the radius.
3) C
The different variables are representing different points on the circles. The circle that contains a line connecting C and L is circle C.
4) BN
Circle B contains a radius that is the distance from B to N, or BN.
5) EF
The diameter is the distance of a straight line that was pass through the middle of a circle, or its width. The diameter is double the radius. In circle A we see that line EF passes through the center put goes all the way across the circle.
6)IJ
Line IJ isn't even linear, so it could not be the radius. Both AG and BH are straight lines that represent the radius.
7) 6"
The diameter is always twice the radius. In circle A the radius is 3, so the diameter is 6.
8) A and D
Just as we said in the first answer, A and D both have a radius that measures 3 inches.
I hope this helps!
Step-by-step explanation:
Answer:
<em>Their masses are 100 kg and 90 kg</em>
Step-by-step explanation:
<u>Equations</u>
We'll solve the problem by setting only one variable. Let's call:
x = weight of the heavier boxer
Since the sum of the masses of both boxers is 190 Kg:
190 - x = mass of the lighter boxer.
It's given that 
of the mass of the heavier boxer is 10 kg less than the mass of the other, thus:
Operating:
Multiplying by 5:
Simplifying:
The heavier boxer's mass is 100 kg. The lighter boxer has a mass of 190-100 = 90 kg.
Their masses are 100 kg and 90 kg
Answer:
pentagram lookin symbol its c btw
Step-by-step explanation:
Answer:
its the lastone
Step-by-step explanation:
