Answer:
138 fluiere, 158 ocarine, 184 viori
Step-by-step explanation:
given:
(1) fluiere + ocarine +viori = 480
(2) fluiere + ocarine =296
(3) ocarine + viori =342
din ecuatia (3) avem: viori= 342-ocarine
din ecuatia(2) avem : fluiere= 296-ocarine
in ecuatia (1) inlocuieste ce ai gasit ca sa fie o ecuatie doar cu necunoscuta ocarine: fluiere + ocarine +viori = 480
296-ocarine +ocarine+ 342-ocarine =480
296+342-480 = ocarine =158
viori = 342-158 = 184
fluiere = 296-158 = 138
Answer:
<h2>2/5 </h2>
Step-by-step explanation:
<h2>Hope it help & study well</h2>
Answer:
-6.1 - (-3.13) = -2.97
Answer:
- r = 12.5p(32 -p)
- $16 per ticket
- $3200 maximum revenue
Step-by-step explanation:
The number of tickets sold (q) at some price p is apparently ...
q = 150 + 25(20 -p)/2 = 150 +250 -12.5p
q = 12.5(32 -p)
The revenue is the product of the price and the number of tickets sold:
r = pq
r = 12.5p(32 -p) . . . . revenue equation
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The maximum of revenue will be on the line of symmetry of this quadratic function, which is halfway between the zeros at p=0 and p=32. Revenue will be maximized when ...
p = (0 +32)/2 = 16
The theater should charge $16 per ticket.
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Maximum revenue will be found by using the above revenue function with p=16.
r = 12.5(16)(32 -16) = $3200 . . . . maximum revenue
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<em>Additional comment</em>
The number of tickets sold at $16 will be ...
q = 12.5(32 -16) = 200
It might also be noted that if there are variable costs involved, maximum revenue may not correspond to maximum profit.
