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sweet [91]
3 years ago
13

Find the measure of each exterior angle of a regular polygon with 22 sides

Mathematics
2 answers:
svet-max [94.6K]3 years ago
8 0

I think it’s 12 I hope this helps

Zina [86]3 years ago
6 0

it's 96 inches around and 2 inches wide

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<img src="https://tex.z-dn.net/?f=%5Csqrt%7B-63%5C%5C" id="TexFormula1" title="\sqrt{-63\\" alt="\sqrt{-63\\" align="absmiddle"
alex41 [277]
Here you go! Hope this helps

4 0
3 years ago
Which is larger 0.035 or 0.17
BabaBlast [244]
0.17 is larger as .035 is in the hundredth spot and is lower in value than the tenth spot, in which 0.17 is at. <span />
7 0
3 years ago
Read 2 more answers
How do i solve this inequality and what is the answer? <br> solve for x: -3x +3 &lt; 6
kap26 [50]

Answer:

x > -1

Step-by-step explanation:

-3x +3 < 6

-3x < 6 - 3  (subtract 3 from both sides)

-3x < 3   (divide both sides by 3)

-x < 1 (multiply both sides by -1, remember to flip the inequality when multiplying both sides by negative numbers)

x > -1  (answer)

5 0
3 years ago
Read 2 more answers
The width of a rectangle is the length minus 4 units. The area of the rectangle is 12 units. What is the width in units of the r
Genrish500 [490]

Answer:

width = 2 units

Step-by-step explanation:

If the length of a rectangle is (x) units, then that means that the width of a rectangle is x - 4 units.

the area of a rectangle is length * width

so just substitute the values that we have now.

x (length) * (x-4) width = 12 (area of rectangle)

so that gives us

x^2 - 4x =12

subtract 12 from both sides

x^2 - 4x - 12 =0

now factor this equation

x^2 + 2x - 6x -12 = 0

x(x+2) - 6(x+2) = 0

(x-6)(x+2) = 0

x = 6, or x = -2 REMEMBER THAT VALUE OF x = LENGTH, IT CANNOT BE NEGATIVE AS YOU CANT HAVE NEGATIVE VALUE OF A SIDE

length = 6, and width = 6 -4 = 2

8 0
3 years ago
Read 2 more answers
The angles of elevation froma point X to the top of flagpoles A and B are 35* and 45* respectively. If X lies in the middle of t
BartSMP [9]

Let AB = t. And since X lies in the middle, so AX=BX = t/2 .

Let the height of the smaller flagpole is AO and of larger flagpole is BP .

Using tangent ratio rule in each triangle, we will get

tan 35 =\frac{AO}{t/2} , tan 45= \frac{BP}{t/2} // AO = \frac{t*tan35}{2},  BP=\frac{t*tan45}{2}

And there ratio is

\frac{AO}{BP}= \frac{tan 35}{tan 45}=\frac{0.7}{1}

5 0
3 years ago
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