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Alex787 [66]
3 years ago
14

I need help on number 10!!! plese and thanks

Mathematics
1 answer:
nikklg [1K]3 years ago
8 0

Answer:

4 5/6

Step-by-step explanation:

4 5/6 = 29/6

5 1/6 = 31/6

29/6 + 31/6 = 60/6 = 10

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A​ hot-air balloon is 140 ft140 ft above the ground when a motorcycle​ (traveling in a straight line on a horizontal​ road) pass
luda_lava [24]

Answer:

Step-by-step explanation:

Given

Balloon velocity is 14 ft/s upwards  

Distance between balloon and cyclist is 140 ft

Velocity of motor cycle is 88 ft/s

After 10 sec  

motorcyclist traveled a distance of d_c=88\times 10=880 ft

Distance traveled by balloon in 10 s

d_b=14\times 10=140 ft

net height of balloon from ground =140+140=280 ft[/tex]

at t=10 s

distance between cyclist and balloon is z=\sqrt{280^2+880^2}

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now suppose at any time t motorcyclist cover a distance of x m and balloon is at a height of h m

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differentiating w.r.t time

\Rightarrow z\frac{\mathrm{d} z}{\mathrm{d} t}=14\cdot \left ( 14t+140\right )+88\cdot \left ( 88t\right )

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\Rightarrow \frac{\mathrm{d} z}{\mathrm{d} t}=\frac{14\times 280+88^2\times 10}{923.471}

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