Equation of line passing through (2, -2) and parallel to 2x+3y = -8 is 
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Need to write equation of line parallel to 2x+3y=-8 and passes through the point (2, -2)
Generic slope intercept form of a line is given by y = mx + c
where "m" = slope of the line and "c" is the y - intercept
Let’s first find slope intercept form of 2x+3y=-8 to get slope of line

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c,

We know that slopes of parallel lines are always equal
So the slope of line passing through (2, -2) is also 
Equation of line passing through
and having slope of m is given by


Substituting the values in equation of line we get



Hence equation of line passing through (2 , -2) and parallel to 2x + 3y = -8 is given as 
K=am+3mx
K=m(a+3x)
m=K/(a+3x)
Answer: m=K/(a+3x)
Answer:
340
Step-by-step explanation:
240 + 100 = 340
9.75
Just divide 195 by 20. You’d get 9.75 as an answer.
using the vertical line test
Graph b is a function