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3 years ago

15

You have 2 buckets. one full of white marbles and the other full of black marbles. how do you allocate the marbles into buckets

in a way that maximizes your probability of picking 2 white ones when you pick 1 marble from each bucket?

1 answer:

butalik [34]3 years ago

4 0

The only way I can think of is to split the buckets in half with half of the black mables and half of the white marbles in each bucket

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Any cut 2 2/4 feet of balsa wood for the length of a kite he cut 3/4 feet for the width of the kite how much longer is the lengt

stellarik [79]

1 3/4 feet longer than the width.

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3 years ago

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Find each sum<br><br> 1. 56 + (-56)<br><br> 2. -240 + 370<br><br> 3. -5.7 + (-4.2)

Zinaida [17]

Answer:

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Solve this question <br>a=7+3

mr Goodwill [35]

Answer:

<h2>10</h2>

Step-by-step explanation:

<em>The answer is 10 because 7 + 3 equals 10!</em>

<em></em>

<em>This can be proven by adding 7 + 3 or by subtracting in a certain way.</em>

<em>7 + 3 = ?</em>

<em>7 + 1 = 8</em>

<em>7 + 2 = 9</em>

<em>7 + 3 = 10</em>

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<em>You can show more work by subtracting your answer or 10 in this case, which means that you subtract 7 by 10 or 3 by 10, either way is ok.</em>

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<em>If you subtract 7 by 10, ( 10 - 7 ) then you get 3</em>

<em>If you subtract 3 by 10, ( 10 - 3 ) then you get 7</em>

<em>If the number you subtracted matches the number that you didn't subtract, then your answer is correct.</em>

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<em>Hope this helps! <3</em>

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3 years ago

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28. Box A weighs 212.04 kilograms. Box B

AlekseyPX

Answer: the answer has to be a because the other ones are not even close

Step-by-step explanation:

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3 years ago

A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.

irakobra [83]

Answer:

The integral is equal to $5\sec^2(2x)+C$ for an arbitrary constant C.

Step-by-step explanation:

a) If $u=\tan(2x)$ then $du=2\sec^2(2x)dx$ so the integral becomes $\int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C$ . (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case $u=\sec(2x)$ hence $du=2\tan(2x)\sec(2x)dx$ . We rewrite the integral as $\int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C$ .

c) We use the trigonometric identity $\tan(2x)^2+1=\sec(2x)^2$ is part b). The value of the integral is $5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C$ . which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.

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3 years ago