Answer:
x^2 - 64
Step-by-step explanation:
A difference of squares is a special product in the form (a^2 - b^2)..their factored form is (a - b)(a + b)..
Thus here a = x and b = 8, thus if x + 8 is a factor, then x - 8 is also a factor..
(x + 8)(x - 8) <-- expand this out using difference of squares rules..
= (x)^2 - (8)^2
= x^2 - 64 <-- answer...
You could also expand that using FOIL (FOIL - first, outer, inner, last)..
(x + 8)(x - 8)
= (x)(x) + (x)(-8) + (8)(x) + (8)(-8)
= x^2 - 8x + 8x - 64 <-- the -8x and 8x cancels out..leaving you with..
= x^2 - 64
Answer:
Step-by-step explanation:
If Amy started with 28 dollars and bought 7 pens, then had 20.30 dollars, we can subtract to find the price of all 7 pens.
28-20.30=7.70 dollars
now to find the amount for EACH pen, we divide by 7
7.70/7=1.1
each pen costed Amy 1 dollar and 10 cents with tax
Answer:
The answer is 31 pennies
Step-by-step explanation:
we have to find a number that gives a remainder of 1 when divided by both 2, 3 and 5.
The easiest way to do this is to list the factors of 5, add 1 to it, and test them until we find the one with a remainder of 1 by all three divisors. This is done as follows:
1) factor: 5 (+1) = 6
6 ÷ 2 = 3 remainder 0
6 ÷ 3 = 2 remainder 0
since there is a remainder of 0, when divided by 3, 6 is wrong
2) factor; 10 (+1) = 11
11 ÷ 3 = 3 remainder 2 ( 11 is not the correct answer
3) factor : 15 (+1) = 16
16 ÷ 2 = 8 remainder 0 ( 16 is not the correct answer
4) factor : 20(+1) = 21
21 ÷ 3 = 7 remainder 0 ( 21 is wrong)
5) factor : 25(+1) = 26
26 ÷ 2 = 13 remainder 0 ( 26 is wrong)
6) factor : 30(+1) = 31
31 ÷ 2 = 15 Remainder 1
31 ÷ 3 = 10 Remainder 1
31 ÷ 5 = 6 Remainder 1
since all three divisors give a remainder of 1, the correct answer is 31
Therefore you have 31 pwnnies
Answer:
(-∞, -4] ∪ [5, ∞)
Step-by-step explanation:
Hi!
Alright, so greater (or less) than or equal to is denoted with a bracket.
If x is less than or equal to -4, then the bracket is on the left side.
(___, -4]
Because x is <em>any</em> number under or equal to -4, x can range from negative infinity. However, we use a parentheses for infinity because infinity can never truly be reached.
So, x 
-4 = (-∞, -4]
X
5
Equal to = bracket
X is any number above 5, so
[5, ∞)
Because we want both of these, we use the union sign (∪)
so,
= (-∞, -4] ∪ [5, ∞)
This is a badly worded problem
