Please help with my geometry
1 answer:
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Answer:
Step-by-step explanation:
The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:
Answer:
i. <DCB =
ii. Sin of <DCB = 0.8
Step-by-step explanation:
Let <DCB be represented by θ, so that;
Sin θ =
Thus from the given diagram, we have;
Sin θ =
= 0.8
This implies that,
θ = 0.8
= 53.1301
θ =
Therefore, <DCB = .
So that,
Sin of <DCB = Sin
= 0.8
Sin of <DCB = 0.8