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3 years ago

What is 706.5 rounded by the nearest hundredth

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

4 0

Answer:

700

Step-by-step explanation:

I think you mean "Hundred", not "Hundredth", since there is no hundredth in this problem.

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Can anyone do 4,5 and 6 for me plz

cricket20 [7]

For question 4, $sinA =\frac{a}{c}, cosA= \frac{b}{c}, tan B = \frac{b}{a}, sin J = \frac{j}{l}, cosK = \frac{j}{l}, tanK = \frac{k}{j}.$

Question 5. Option a and question 6. Option j

Step-by-step explanation:

Step 1:

The three basic formula needed to solve these questions are:

$sin\theta = \frac{oppositeside}{hypotenuse} , cos\theta = \frac{adjacentside}{hypotenuse}, tan\theta= \frac{opposite side}{adjacent side}.$

Step 2:

Using the above formula, we solve the following values

$sinA = \frac{oppositeside}{hypotenuse}$ $=\frac{a}{c}.$

$cosA = \frac{adjacentside}{hypotenuse}$ $= \frac{b}{c}.$

$tanB= \frac{opposite side}{adjacent side}$ $= \frac{b}{a}.$

$sinJ = \frac{oppositeside}{hypotenuse}$ $= \frac{j}{l}.$

$cosK = \frac{adjacentside}{hypotenuse}$ $= \frac{j}{l}.$

$tanK= \frac{opposite side}{adjacent side}$ $= \frac{k}{j}.$

Step 3:

For question 5, The triangle's angle = 23°, opposite side = BC inches and hypotenuse = 4 inches.

$sin\theta= \frac{opposite side}{hypotenuse}. sin 23^{\circ}= \frac{BC}{4}, sin23^{\circ} = 0.3907,BC = (0.3907)(4) = 1.5628.$

SO BC is 1.5628 inches, rounding this off to the nearest tenth, we get BC = 1.6 inches which is option a.

Step 4:

For question 6, The triangle's angle = 50°, opposite side = QR m the adjacent side = 8.1 m.

$tan\theta= \frac{opposite side}{adjacentside}. tan 50^{\circ}=\frac{QR}{8.1}, tan50^{\circ} = 1.1917,QR = (1.1917)(8.1) = 9.65277$

SO QR is 9.65277 meters, rounding this off to the nearest tenth, we get QR = 9.7 inches which is option j.

7 0

3 years ago

I need help asap pleaseeeeeee

skad [1K]

Step-by-step explanation:

if the volume of a cylinder is given by v=pi*h*r^2 lets find each volume and find their ratio. volume of a is 50.24 and volume of c is 200.96. so the ratio is 200.96:50.24. let's simply this by saying 200.96/50.24 to see how many of the smaller cylinders A it takes to equal 1 of the larger cylinder C. it is 4. the ratio is 1:4. 1 large cylinder C is equal to 4 smaller cylinders A

8 0

3 years ago

Read 2 more answers

Question 9 of 10

Nonamiya [84]

The answer is B. 0.02
1/2 (100)(h) = 1
h= 2/100
=h = 0.02

8 0

3 years ago

The unit rate of $34 in 8 hours

Luden [163]

It would be $4.25 per hour.

4 0