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3 years ago

Find 2 consecutive odd integers such that 3 times the larger is 29 more than 3 times the smaller

1 answer:

4 0

$x,\ x+2-two\ consecutive odd integers\\\\3(x+2)=3x+29\\\\3x+6=3x+29\ \ \ |-3x\\\\6=29\ \ \ FALSE\\\\Answer:\ \text{such numbers do not exist}$

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Mixed in a drawer are 44 blue socks, 88 white socks, and 44 gray socks. You pull out two socks, one at a time, without looki

MrRissso [65]

Answer:

The probability of getting 2 socks of the same color is 1/3.

Step-by-step explanation:

In the drawer,

Number of blue socks = 4

Number of white socks = 8

Number of gray socks = 4

Total number of socks = 4 + 8 + 4 = 16

Total ways to select 2 socks form 16 socks is

$^{16}C_2=\dfrac{16!}{2!(16-2)!}=120$

Total ways to select 2 socks of the same color is

T = Possible ways of (2 blue + 2 white +2 gray) socks

= $^{4}C_2+^{8}C_2+^{4}C_2$

= $6+28+6$

= $40$

The probability of getting 2 socks of the same color is

$Probability=\dfrac{\text{Total ways to select 2 socks of the same color}}{\text{Total ways to select 2 socks form 16 socks}}$

$Probability=\dfrac{40}{120}$

$Probability=\dfrac{1}{3}$

Therefore, the probability of getting 2 socks of the same color is 1/3.

3 0

3 years ago

WILL GIVE BRAINLIEST Just need the answer

Monica [59]

Answer: B

Step-by-step explanation:

7 0

2 years ago

Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)

Leni [432]

Alrighty

remember some rules
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}=\frac{1}{x^m}$
and
$x^0=1$ for all real values of x
and
$(a^b)^c=a^{bc}$
and
$(\frac{a}{b})^c=\frac{a^c}{b^c}$
and
(a/b)/(c/d)=(ad)/(bc)
and
$(a^b)(a^c)=a^{b+c}$
and
$\frac{a^m}{a^n}=a^{m-n}$
and don't forget pemdas
example: $-x^m=-1(x^m)$ but $(-x)^m=(-1)^m(x^m)$

so

4.
$(\frac{c^{-2}}{2})^{-2}=$

$\frac{(c^{-2})^{-2}}{2^{-2}}=$

$\frac{c^4}{\frac{1}{2^2}}=$

$\frac{c^4}{\frac{1}{4}}=$

$4c^4$

5.

$\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=$

$\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=$

$\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=$

$\frac{(a^4bc^5)b^3}{(-1)(a^2)}=$

$\frac{-a^4b^4c^5}{a^2}=$

$-a^2b^4c^5$

3 0

3 years ago

these tables of values represent continuous functions. for which function will the y-value be the greatest for very large values

Gelneren [198K]

Answer:

Option A.

Step-by-step explanation:

We need to find a table for which the y-value will be the greatest for very large values of x.

From the given table it is clear that the largest value of x in all tables is 5.

In table A, y=64 at x=5.

In table B, y=32 at x=5.

In table C, y=40 at x=5.

In table D, y=13 at x=5.

It is clear that 64 is the greatest value among 64, 32, 40 and 13.

It means table in option A represents the function for which the y-value will be the greatest for very large values of x.

Therefore, the correct option is A.

3 0

3 years ago

Question: What is the value of the expression shown? 24 − 52

KatRina [158]

Answer:

-28

Step-by-step explanation:

52-24= 28

so the opposite

24-58= -28

3 0

3 years ago