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AfilCa [17]
3 years ago
10

List the set of integers leas than -8

Mathematics
2 answers:
Oksana_A [137]3 years ago
5 0

Any rational number that is -9 up (-10, -11, -12, etc.) is an integer less than -8

Alex73 [517]3 years ago
3 0
-9 and Everything above it(-10,-11,-12,-13)
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Simplify completely: 2 square root -45
iogann1982 [59]

Answer:

Step-by-step explanation:

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6 0
4 years ago
Danielle and Drew are sightseeing for the day. Between the two of them they take 77 pictures. Danielle takes 17 more than twice
Alex Ar [27]
Let's break this down:
Total Pictures = 77
Drew's Pictures = X (An unknown amount)
Danielle's Pictures = 17 + 2X (2 times the amount of Drew plus 17)

So, let's put the pieces together, the problem should look like this:
   Total Pictures = Drew's Pictures + Danielle's Pictures

So let's put in what we know:
   77 = X + (17 + 2X)

1st step is to get X to one side:
   77 = X + 17 + 2X
   -17       - 17
=> 60 = X + 2X
=> 60 = 3X

Now that X is on one side, the 2nd step is to get X to be alone:
   60/3 = 3X/3  (We have to divide to each side because the answer is equal)
   20 = X

So, now that we know what X equals, let's go back to what we broke down:
Drew's Pictures = X (An unknown amount)
Danielle's Pictures = 17 + 2X (2 times the amount of Drew plus 17)

*Remember that X = 20*
So the amount of Drew's Pictures (since the amount is equal to X) is 20.

Danielle had 17 + 2X pictures which means:
17 + 2(20)
17 + 40
57

So Danielle took 57 pictures
7 0
3 years ago
Is (5,1) a solution to the equation 2x-y=11? Explain
grigory [225]
This is simple. Coordinate form is (x,y) so you would just plug in your values. 

2(5)-(1)=11

10-1 does not equal 11, so no it is not a solution.
7 0
4 years ago
Read 2 more answers
Hi, can someone please answer this question? Thanks!!!
cricket20 [7]

Answer:

sorry im not so sure abut the answer

Step-by-step explanation:

.....

8 0
4 years ago
Can someone please answer 11 and 13 for me? its quadratics by factoring.
poizon [28]
11. 7,  or -1 
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0(x) will always be 0 
5 0
3 years ago
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