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AleksandrR [38]
3 years ago
8

Which equation represents the statement thirteen less then a number is forty two

Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
4 0

Answer:

The equation which represents the statement thirteen less then a number is forty two is:

x-13=42

Step-by-step explanation:

Let x be any number

we are given that:

thirteen less then a number is forty two

i.e. x-13=42

Hence, the equation which represents the statement thirteen less then a number is forty two is:

x-13=42

Ludmilka [50]3 years ago
3 0
X-13=42 
x is the "variable", you're taking 13 away from that, and the answer is also given, 42. 
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The length of a rectangle is four times its width. If the perimeter of the rectangle is 90 cm, find its area
Sunny_sXe [5.5K]

Answer:

324

Step-by-step explanation:

L = 4W

P = 2L + 2W = 90

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2L + 2W = 90

2(4W) + 2W = 90

8W + 2W = 90

10W = 90

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W = 9

L = 36

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A = 324

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Write and solve an inequality that represents the values of x, in feet.
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Answer:

x < 16 ft

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Perimeter = x

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x < 16

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A professor has recorded exam grades for 10 students in his​ class, but one of the grades is no longer readable. If the mean sco
Nostrana [21]

Answer:

unreadable score = 35

Step-by-step explanation:

We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".

There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":

1) The mean score of ALL exams (including the unreadable one) is 80

so the equation to represent this statement is:

mean of ALL exams = 80

By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:

\frac{R+x}{10} =80

since the mean is the addition of all values divided the total number of exams.

in a similar way we can write what the mean of just the readable exams is:

\frac{R}{9} = 85\\ (notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.

Based on the equation above, we can find what "R" is by multiplying both sides by 9:

\frac{R}{9} = 85\\R=85*9= 765

Therefore we can now use this value of R in the very first equation we created, and solve for "x":

\frac{R+x}{10} =80\\\frac{765+x}{10} =80\\765+x=80*10=800\\765+x=800\\x=800-765=35

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3 years ago
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