Answer:
First Game: 65 points
Second Game : 65 points
Third Game : 59 points
Step-by-step explanation:
Average = sum of values/number of values
The number of values = 3, an d average = 63
63 = x/3
63 * 3 = x
189 = x
Now 189 is the sum of points over two games.
Their first two games are worth the same, so lets call that s +s = 2s
Their 3rd game is worth 6 less points than s, so s-6
let's add up all the terms:
2s + (s - 6) = 3s - 6
Solve:
3s - 6 = 189
3s = 195
s = 65
The first two games are worth 65, and the third game is worth 65 - 6 = 59.
-Chetan K
2x + 3 = 4x + 2
3 - 2 = 4x - 2x
1 = 2x
x = 1/2
Its B 1 solution
