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Dafna1 [17]
3 years ago
6

Write an explicit rule in function form for the sequence represented by the given terms.

Mathematics
1 answer:
hram777 [196]3 years ago
5 0

Answer:

The general relation about a geoemtric sequence is

a_{n}=a_{1}r^{n-1}

For the first sequence, we have

3=a_{1}r^{5-1}

147=a_{1}r^{7-1}

Which is a system of equations. We can isolate a variable in the first equation to replace that expression into the second equation.

a_{1}=\frac{3}{r^{4} }

147=\frac{3}{r^{4}  }r^{6}

r^{2}=\frac{147}{3}\\  r=\sqrt[2]{49}\\r=7

Now, we replace this value to find the other one

3=a_{1}(7)^{4}\\ a_{1}=\frac{3}{2401}

Therefore, the explicit rule function is

a_{n}=\frac{3}{2401}  \times (7)^{n-1}

Now, we use the same process for the second sequence.

10=a_{1}r^{3-1}  \\a_{1}=\frac{10}{r^{2} }

The second equation is

1440=a_{1}r^{5-1}\\a_{1}=\frac{1440}{r^{4} }

Now, we solve the following expression

\frac{10}{r^{2} }=\frac{1440}{r^{4} }

We solve for r

\frac{r^{4} }{r^{2} }=\frac{1440}{10}\\r^{2}=144\\ r=\sqrt{144} \\r=12

Then

a_{1}=\frac{10}{(12)^{2} }  =\frac{10}{144}=\frac{5}{72}

Therefore, the function that models the second sequence is

a_{n}=\frac{5}{72} \times (12)^{n-1}

Notice that a_{n} is the dependent variable and n is the independent variable.

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