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2 years ago

Calculate the mean. 4, 5, 7, 7, 9, 12, 15, 20

Mathematics

1 answer:

Semmy [17]2 years ago

5 0

Answer:

Mean: 9.875

Median: 8

Mode: 7

Minimum: 4

Maximum: 20

Range: 16

Size: 8

Sum: 79

Step-by-step explanation:

How to find the mean?

1. Count the number N of data points in your data set.

2. Sum up all of the data points in your data set (add them all together).

3. Average = Mean = Sum/N.

How to find the median ?

The median is the numeric value separating the upper half of a sample data set from the lower half. The median of a data set can be found by arranging all the values from lowest to highest value and picking the one in the middle. If there is an odd number of data values then the median will be the value in the middle. If there is an even number of data values the median is the mean of the two data values in the middle.

For the data set 1, 1, 2, 5, 6, 6, 9 the median is 5.

For the data set 1, 1, 2, 6, 6, 9 the median is 4. It is the mean of 2 and 6 or, (2+6)/2 = 4.

How to find the mode

Mode is the value or values in the data set that occur most frequently.

For the data set 1, 1, 2, 5, 6, 6, 9 the mode is 1 and also 6.

Hope this helps you! :D

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You pick a card at random 2,3,4,5 what is P(2)

Luden [163]

Total possible outcomes = 4

Total no. of favorable outcomes = 2

$\sf \: P(2) = total \: no. of \: favorable \: outcomes/ total \: no. \: of \: possible \: outcomes \\ = \frac{2}{4} \\ = \frac{1}{2}$

8 0

3 years ago

Read 2 more answers

−6−1.5(4b+8)=3(−6−2b)

____ [38]

Answer:

-18 = -18 It is true.

Step-by-step explanation:

-6 -1.5(4b+8) = 3(-6 -2b)

-6 -6b - 12 = -18 -6b

-6b -18 = -18 -6b

+6b +6b

-18 = -18

It is true.

4 0

2 years ago

HELP PLEASE!!! I need help with 94 if you could show the steps that would be very helpful!

aksik [14]

A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:

n!/((n-r)!r!)

In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.

5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5

5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10

5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10

5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5

Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.

Now we add together the combinations

1 + 5 + 10 + 10 + 5 + 1 = 32 choices combinations to discard.

The answer is 32.

-------------------------------

Note: There is also an equation for permutations which is:

n!/(n-r)!

Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.

We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.

I hope this helps! If you have any questions, let me know :)

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3 years ago

(0.2c^3)^2–0.01c^4(4c^2–100)

Debora [2.8K]

The answer should be C^4

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3 years ago

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8n-(2n-3)=12 solve for n

Feliz [49]

8n-(2n-3)=12
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3 years ago

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