What is the difference between plotting (2, 3) and (3, 2) on a coordinate plane? Explain

Mathematics

2 answers:

Ronch [10]4 years ago

7 0

These points are similar.

They both lie in quadrant 1.

However, the x coordinate is different in each ordered pair.

So (3, 2) moves farther from the origin than (2 , 3).

However, (2, 3) moved farther up than (3, 2).

Take a look below.

katen-ka-za [31]4 years ago

4 0

Answer:

see below (I hope this makes sense and I hope it helps!)

Step-by-step explanation:

Points are found in the form (x, y) where x represents the x - value which is basically how far you move from the origin on the x-axis, and the same goes for y except it represents how far you move from the origin on the y-axis. A positive x means you move right, a negative x means you move left, a positive y means you move up and a negative y means you move down. Following these rules, to plot (2, 3), you move 2 units right and 3 units up from the origin and to plot (3, 2), you move 3 units right and 2 units up from the origin. The difference between plotting the two points is that first of all, they are different points so they are in different locations and second, their coordinates are "flipped"; what I mean by that is the x-coordinate of the first point is the y-coordinate of the second point and vice versa. Therefore, you move the same amount but in different directions.

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4.9t+0.3=5.6t+0.72 I need help on my work lol

Whitepunk [10]

The first step that we must take before attempting to solve the problem is to understand what the problem is asking us to do and what is given to us to help accomplish that goal. Although it does not explicitly state that we must solve for t, this is usually what the problem statement would be asking if we just receive and expression like this. What is given to us to accomplish that goal is the expression $4.9t+0.3=5.6t+0.72$ .

Now that we have completed that step, we can move onto the next part which is actually solving the problem. The next step that we should take when solving for the unknown, in this case t, is to subtract 4.9t from both sides.

Subtract 4.9t from both sides

$4.9t+0.3=5.6t+0.72$

$(4.9t-4.9t)+0.3=(5.6t-4.9t)+0.72$

$0.3=(5.6t-4.9t)+0.72$

$0.3=(0.7t)+0.72$

Now that we got all of the t's to one side, let us isolate t completely and the next step that we should take is to subtract 0.72 from both sides.

Subtract 0.72 from both sides

$0.3=0.7t+0.72$

$0.3 - 0.72=0.7t+0.72 - 0.72$

$0.3 - 0.72=0.7t$

$-0.42=0.7t$

The final step that we need to take to isolate t would be to divide both sides by 0.7 which would remove the coefficient from the unknown variable t and divide 0.7 from -0.42

Divide both sides by 0.7