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jok3333 [9.3K]
2 years ago
12

4.9t+0.3=5.6t+0.72 I need help on my work lol

Mathematics
1 answer:
Whitepunk [10]2 years ago
5 0

The first step that we must take before attempting to solve the problem is to understand what the problem is asking us to do and what is given to us to help accomplish that goal.  Although it does not explicitly state that we must solve for t, this is usually what the problem statement would be asking if we just receive and expression like this.  What is given to us to accomplish that goal is the expression 4.9t+0.3=5.6t+0.72.

Now that we have completed that step, we can move onto the next part which is actually solving the problem.  The next step that we should take when solving for the unknown, in this case t, is to subtract 4.9t from both sides.

<u>Subtract 4.9t from both sides</u>

  • 4.9t+0.3=5.6t+0.72
  • (4.9t-4.9t)+0.3=(5.6t-4.9t)+0.72
  • 0.3=(5.6t-4.9t)+0.72
  • 0.3=(0.7t)+0.72

Now that we got all of the t's to one side, let us isolate t completely and the next step that we should take is to subtract 0.72 from both sides.

<u>Subtract 0.72 from both sides</u>

  • 0.3=0.7t+0.72
  • 0.3 - 0.72=0.7t+0.72 - 0.72
  • 0.3 - 0.72=0.7t
  • -0.42=0.7t

The final step that we need to take to isolate t would be to divide both sides by 0.7 which would remove the coefficient from the unknown variable t and divide 0.7 from -0.42

<u>Divide both sides by 0.7</u>

  • -0.42=0.7t
  • \frac{-0.42}{0.7}=\frac{0.7t}{0.7}
  • \frac{-0.42}{0.7}=t
  • -0.6=t

Therefore, after fully narrowing down the solution we were able to determine that the solution of the unknown variable or t is equal to -0.6

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The circumference of the tree trunk is 7.85
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2.5 feet

Step-by-step explanation:

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A pan of warm water (46∘ Celsius) was put in a refrigerator. After 15 minutes, the water's temperature was 27∘ C; 15 minutes aft
Cloud [144]

Answer:

The refrigerator was at around 13 ∘C

Step-by-step explanation:

Newton's Law of Cooling:

The rate of change of a body temperature  (amount of heat loss/time of loss) is directly proportional to the difference between its own temperature and the surroundings.

\frac{T(t2)-T(t1)}{t2-t1} = -h (T(t2) - Tenv)

T ⇒ temperature

t ⇒ time

Tenv ⇒refrigerator temperature

\frac{T(t2)-T(t1)}{t2-t1} ⇒ rate of change of he temperature

-h ⇒ constant of proportionality (negative because the temperature is decreasing inside the refrigerator)

We have 3 points:

time (minutes) - Temperature (∘ C)

0 (when the pan was put in the refrigerator) - 46

15 (after 15 minutes) - 27

30 (15 minutes after the first 15 minutes) - 19

\frac{27 - 46}{15 - 0} = -h (27 - Tenv)

\frac{19 - 27}{15 - 0} = -h (19 - Tenv)

Now we have a system of two equations and two variables

\frac{-19}{15} = -h (27 - Tenv)\\ \frac{19}{15} = h (27 - Tenv)\\ \frac{19}{15(27 - Tenv)} = h

\frac{19 - 27}{15 - 0} = -h (19 - Tenv)\\\frac{-8}{15} = -h (19 - Tenv)\\\frac{8}{15} = h (19 - Tenv)\\\frac{8}{15} = \frac{19}{15(27 - Tenv)} (19 - Tenv)\\8(27 - Tenv) = 19 (19 - Tenv)\\216 - 8 Tenv = 361 - 19 Tenv\\19 Tenv - 8 Tenv = 361 - 216\\11 Tenv = 145 \\Tenv = 145/ 11\\Tenv = 13. 18

The refrigerator was at around 13 ∘C

6 0
3 years ago
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