What is the absolute value of the complex number -4 -√2i ?

Mathematics

2 answers:

spin [16.1K]3 years ago

7 0

Answer:

$3\sqrt{2}$

Step-by-step explanation:

We need to find the absolute value of the complex number -4 -√2i

to find absolute value of any complex number we use formula

|a+bi| = $\sqrt{a^2+b^2}$

-4 -√2i , here a=-4 and b=-sqrt(2)

$|-4-\sqrt{2}i|} =\sqrt{(-4)^2+(-\sqrt{2})^2}$

= $\sqrt{16+2}$

= $\sqrt{18}$

= $3\sqrt{2}$

Alenkasestr [34]3 years ago

4 0

Answer:

the answer is b. 3 sqrt 2

Step-by-step explanation:

I took the test on edge

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3 1/2 - 4 2/5<br> how do i do this?

Nadusha1986 [10]

Answer:

Ok so first you would have to turn them into improper fractions which is

3 $\frac{1}{2\\}$ = $\frac{7}{2}$ and 4 $\frac{2}{5}$ = $\frac{22}{5}$

So now that you have made them both improper fractions you have to find common denominators.

To find common denominators you must multiply both the numerator and the denominator by the same thing. Since your oposing fraction has a denominator of 5 you can know that a even number wont go in an odd number so take $\frac{22}{5}$ and mutiply both numbers by 2 and get $\frac{44}{10}$ . Then mutiply both numbers in $\frac{7}{2}$ by 5 to get a common denominator.