Let d be distance travelled when they are level , and t = time that nora took to get level with mason
for Nora
6 = d/t
d = 6t
for Mason
5 = d / (t + 35)
d = 5 ( t + 350
so 6t = 5(t + 35)
solve for t
The answer is −3.555555555555556 but you can just put -3.55
Answer:
Hence average rate of change is greater for f(x) in (0,3).
Yes. f(x) is greater than g(x) in the interval (0,3)
Yes. g(3) <f(3)
Step-by-step explanation:
To find average rate of change of f and g in (0,3)
f(3)-f(0)/3 = (9-0)/3 =3
g(3) = -9-18 = -27
g(0) = 0
Rate of change in(0,3) of g(x) = -27/3 =-9
Hence average rate of change is greater for f(x) in (0,3)
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Both f and g have intercepts of y as 0
Hence both are equal.
3) Yes. f(x) is greater than g(x) in the interval (0,3)
Because g(x) <0 for all x in (0,3) while f(x) >0
4) g(3)= -9-18=-27 <f(3)
Step-by-step explanation:
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62 + x = 82
Subtract both sides by 62.
x = 20.
