Answer:
z = 18,46%
Explanation:
First we need to discover the mole number of the O2 produced so we use PV=nRT
734 torr * 57.2*10^-3 L = n 62.3637 * 295.15 K
n = 
n = 
n = 2,28 * 10^-3 mole
The reaction to the decomposition is:
2 NaClO3 --> 2 NaCl + 3 O2
2 mole NaClO3 - 3 moles O2
x - 2,28*10^-3 moles O2
X= 1,52*10^-3 moles of NaClO3
1 moles of NaClO3 - 106,44 g
1,52*10^-3 moles of NaClO3 - y
y = 0,1617 g
0,8765 g - 100%
0,1617 g - z
z = 18,46%
Element Symbol # of Atoms
Iron Fe 2
Oxygen O 12
Sulfur S 3
Hope this Helps!
<span>Balanced chemical equation is :
2LiCl(s) ----> 2Li(s) + Cl2(g)
</span>
From the given pH, we calculate the concentration of H+:
[H+] = 10^-pH = 10^-5.5
We then use the volume to solve for the number of moles of H+:
moles H+ = 10^-5.5M * 4.3x10^9 L = 13598 moles
From the balanced equation of the neutralization of hydrogen ion by limestone written as
CaCO3(s) + 2H+(aq) → Ca2+(aq) + H2CO3(aq)
we use the mole ratio of limestone CaCO3 and H+ from their coefficients, which is 1 mole of CaCO3 is to react with 2 moles of H+, to compute for the mass of the limestone:
mass CaCO3 = 13598mol H+(1mol CaCO3/2mol H+)
(100.0869g CaCO3/1mol CaCO3)(1kg/1000g)
= 680 kg
