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lozanna [386]
3 years ago
10

I neeeed help realy bad

Mathematics
1 answer:
77julia77 [94]3 years ago
3 0

Answer: -3x + 4, (2,-2)

Step-by-step explanation:

First, you want to get y alone on one side.

3x + y = 4

     -4    -4        subtract 4 to get it on the left side.

     -y     -y       subtract y to get it alone on the right side.

Your'e left with 3x - 4 = -y      divide the whole equation by -1 do get a pos y

You then have y = -3x + 4. That's the first part of your answer.

To get the second part plug in (-3x + 4) into the y of the first equation, this is the substitution part.

-2x + 5(-3x+4) =-14        distribute the 5...     -2x - 15x +20 = -14

add your like terms ( x and x)                       -17x + 20 = -14

Isolate your x by subtracting the 20, both sides  -20   -20

-17x = -34    divide both side by 17 you get x = 2 (---- this is your first coordinate in the pair in your answer. To get the y do the same but solve for y instead of x.

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\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
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\begin{cases}
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\begin{array}{llll}
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