Yup its 53 Degrees you got it right :)
Consider the function
, which has derivative
.
The linear approximation of
for some value
within a neighborhood of
is given by
Let
. Then
can be estimated to be
![\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B63.97%7D%5Capprox4-%5Cdfrac%7B0.03%7D%7B48%7D%3D3.999375)
Since
for
, it follows that
must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function
. This means the estimated value is an overestimation.
Indeed, the actual value is closer to the number 3.999374902...
The percent of his monthly income that will be budgeted for the utilities will be approximately 5.21%.
According to the question,
We have the following information:
Greg evaluated his spending and found that he was spending about $50 more per month on utilities than he has budgeted. He can transfer money from other categories to increase his utilities budget to $125 per month. If his total monthly income is $2,400.
Now, let's take the percent to be x.
We have the following expression:
2400*x/100 = 125
24x = 125
x = 125/24
x = 5.21%
Hence, the percent of his monthly income that will be budgeted for the utilities will be approximately 5.21%.
To know more about percent here
brainly.com/question/28063156
#SPJ4
Since adding a constant to a function simply moved the graph upwards by that amount, solve f(x) for any value and see how much the graph given is different from that value of y...the simplest way in this case may be to simply find f(0) which is:
5*2^0=5
Clearly the graph at x=0 is at y=-2 so we can see that k is:
5+k=-2 so
k=-7
Answer:
160 is the answer please tell me if im wrong
