Question

ests for tuberculosis like all other diagnostic tests are not perfect. QFT-G is one of such tests for tuberculosis. Suppose that for the population of adults that is taking the test, 5% have tuberculosis. The test correctly identifies 74.6% of the time adults with a tuberculosis and correctly identifies those without tuberculosis 76.53% of the time. Suppose that POS stands for the test gives a positive result and S means that the adult really has tuberculosis. Represent the "76.53%" using notation. Group of answer choices P(S) P(Sc) P(POSc | Sc) P( POSc | C)

Answer 1

Answer:

P(POSc/Sc)

Step-by-step explanation:

As,

POS= Test has positive results

and

S=Adult has tuberculosis.

The test correctly identifies 74.6% of the time adults with a tuberculosis and correctly identifies those without tuberculosis 76.53% of the time.

In the above statement 76.53% describes the probability of adult who don't have tuberculosis gets the negative results as test is correctly identifying.

So, getting negative results means that not positive results and for this event the notation of complement POSc is used. Also, not having tuberculosis can be denoted as Sc. So,

POSc= Test has negative results

Sc=Adult hasn't tuberculosis

Thus, P(POSc/Sc) depicts the probability of adults not having tuberculosis gets correct results.

Hence,  P(POSc/Sc)=76.53%