Question

The length of a rectangle is 5 cm more than twice it's width, the perimeter of the rectangle is 34cm, find the length and width of the rectangle

Answer 1

2W + 2L = 34
2W + 2(2W+5)
2W + 4W + 10 = 34
Add the Ws:
6W + 10 = 34

Subtract 10 from each side:
6W = 24
W = 4

Answer 2

The formula for the perimeter of rectangle is 2 times the length plus 2 times the width
2L x 2W
Since the perimeter is 34, 2L x 2W = 34
Also, since the length is 5 more than, or 5 added to the width (5 + W), Length = 5 + Width
If you put it in
2(5+W)+2W=34
10 + 2W + 2W=34
10 + 4W = 34
4W = 34 (-10)
4W = 24
W= 24/4
W=6

L=W+5
L=5+6
L=11

W = 6, L=11