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Llana [10]
3 years ago
8

What linear function equation has a line that goes through both (-1,4) and (3,2)

Mathematics
1 answer:
Ede4ka [16]3 years ago
8 0

Answer:

The equation would be y = -1/2x + 7/2

Step-by-step explanation:

To find the equation, we first need to use the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (2 - 4)/(3 - -1)

m = -2/4

m = -1/2

Now that we have that, we can use that and a point to find the full equation.

y - y1 = m(x - x1)

y - 2 = -1/2(x - 3)

y - 2 = -1/2x + 3/2

y = -1/2x + 7/2

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What do the following two equations represent -2x+2y=5 5x+y=2
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Answer:

points because it is the equation is slope-intercept form

6 0
3 years ago
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What is a quadrilateral with opposite sides that are parallel,4 sides that are the same length,and no right angles?
STALIN [3.7K]
The shape you describe is a rhombus. 
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2 years ago
you can speed from 0 to 25 m/s in 25 seconds and your friend can speed up from 0 to 6 m/s in 6 seconds. who is faster
aksik [14]

Answer:

Neither; see below

Step-by-step explanation:

Your acceleration: a=\frac{\Delta v}{\Delta t}=\frac{25-0}{25}=1m/s^2

Your friend's acceleration: a=\frac{\Delta v}{\Delta t}=\frac{6-0}{6}=1m/s^2

Therefore, since both you and your friend accelerate at the same rate, neither is faster.

7 0
2 years ago
a store owner wishes to make a new tea with a unique flavor by mixing black tea and oolong tea. if he has 35 pounds of oolong te
Verizon [17]

35 pounds of black tea is needed to be mixed to get the final mixture for 2.10 per pound

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the amount of black tea worth 1.80 per pound to be mixed to get the final mixture for 2.10 per pound, hence:

2.4(35) + 1.8(x) = 2.1(x + 35)

x = 35 pounds

35 pounds of black tea is needed to be mixed to get the final mixture for 2.10 per pound

Find out more on equation at: brainly.com/question/2972832

#SPJ1

3 0
2 years ago
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

4 0
3 years ago
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