Answer:
Lower confidence limit = 20.191
Step-by-step explanation:
Sample mean; x' = 22
Sample standard deviation; s = 5.5
Sample size; n = 50
Confidence interval = 99%
Since sample size > 30, we will use the formula;
CI = x' ± zs/√n
Where;
x' is sample mean
s is sample standard deviation
n is sample size
z is z-value of the confidence interval
From the table attached, z for 99% = 2.3263
Thus;
CI = 22 ± (2.3263 × 5.5)/√50
CI = 22 ± 1.809
CI = 23.809 or 20.191
Lower confidence limit = 20.191
Step-by-step explanation:
standard deviation of $3
Find a 98% confidence interval about the mean (one decimal place).
Is a value of X=48 unusually high or is it normal? Choose correct explanation
Answer:
Step-by-step explanation:
The best approximation of the flow rate of the Mississippi River is .
X^2 - 10x + 8 =0
x^2 - 10 + (-10/2)^2 - (-10/2)^2 + 8 = 0
(x - 5)^2 - 25 + 8 = 0
(x - 5)^2 - 17 = 0
To be honest , this is the final step for this equation. It seems like there is no any suitable answer for this question..
To me , I think the best answer will be the third option.
x - 5 =0
x = 5
2x-10 = 0
2x = 10
x = 5
I guess this answer seems like legit.. So I will choose the third option.
the answer to your equation is 42 2/7
