Yeah, x= 7/2 and y= -5/2
Please mark as brainliest and I hope this helps
Start with

We observe that both fractions are not defined if
. So, we will assume
.
We multiply both numerator and denominator of the first fraction by 3 and we sum the two fractions:

We multiply both sides by
:

We move everything to one side and solve the quadratic equation:

We check the solution:

which is true
Answer:
c
Step-by-step explanation:
X=1, x=-7 would be the correct answer.
Answer:
take the population mean divided by four
Step-by-step explanation: